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Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature It at room temperature, 100w, 60w and 40w bulbs have filament resistances $R_100 , R_60 and R_ 40$ respectively the relation between these resistances is

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Explanation

The power rating of a bulb is given by P = V^2 / R, where P is the power, V is the voltage, and R is the resistance. For bulbs with different wattages at the same voltage, the resistance is inversely proportional to the power rating. Therefore, the bulb with the highest wattage will have the lowest resistance. Thus, R_100 < R_60 < R_40, which implies 1/R_100 > 1/R_60 > 1/R_40.

Column I
(a) The unit of electrical resistivity is (b) The unit of current density is (c) The unit of electrical conductivity is (d) The unit of electric mobility is Column II (p) $ m^2S^-1V^-1$ (q) $ \Omega ^ {-1} m^{-1}$ (r.) $ Am^{-2}$ (s) $ \Omega m$

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Explanation

The units of the given physical quantities are: (a) Electrical resistivity: Ωm, (b) Current density: A/m^2, (c) Electrical conductivity: Ω^-1m^-1, (d) Electric mobility: m^2s^-1V^-1. Matching these units to the corresponding quantities in Column II, we get: a - s, b - r, c - q, d - p.

Match the physical quantities given in column I with their dimensional formulae given in column II -I stands for the dimension of current. Column I (a) Electromotive force (emf) (b) Resistance (c) Resistivity (d) Conductivity Column II (p) $ [ M L^2T^{3} A^{-2}]$ (q) $ [ M L^3T^{-3} A^{-2}]$ (r ) $ [ M^{-1} L^{-3}T^{3} A^{2}]$ (s) $ [ M L^2T^{-3} A^{-1}]$

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Explanation

The dimensional formulas for the given physical quantities are: (a) Electromotive force (emf): [ML^2T^-3A^-1], (b) Resistance: [ML^2T^-3A^-2], (c) Resistivity: [ML^3T^-3A^-2], (d) Conductivity: [M^-1L^-3T^3A^2]. Matching these dimensional formulas to the quantities in Column II, we get: a - s, b - p, c - q, d - r.

Assertion and reason type question: Assertion and reason are given in following questions each question has four options one of them is correct select it. Assertion: There is no current in the metals in the absence of electric field. Reason: Motion of free electrons is random.

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Explanation

In metals, the motion of free electrons is indeed random in the absence of an electric field, which means that there is no net current. The assertion states that there is no current in metals without an electric field, and the reason given is that the motion of free electrons is random. Both statements are true, and the reason correctly explains the assertion.

The potential difference between points A and B is - 

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Explanation

Current in loop = 3 A

$V_A - V_B$ = 3 + 2 - (1 ohm) (3A) = 2 V

Assertion and reason type question: Assertion and reason are given in following questions each question has four options one of them is correct select it. Assertion: A potentiometer of longer length is used for accurate measurement. Reason: The potential gardient for a potentiometer of longer length with a given source of e.m.f become small.

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Explanation

A potentiometer is a device used for measuring the potential difference accurately. A longer length potentiometer wire allows for a smaller potential gradient, which makes the measurements more accurate. Thus, the assertion that a potentiometer of longer length is used for accurate measurement is true, and the reason that a longer length results in a smaller potential gradient is also true and correctly explains the assertion.

Assertion and reason type question: Assertion and reason are given in following questions each question has four options one of them is correct select it. Assertion: The 200w bulbs glow with more brightness than 100w bulbs. Reason: A 100w bulb has more resistance than a 200w bulb.

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Explanation

A 200W bulb glows with more brightness than a 100W bulb because it consumes more power. The reason given is that a 100W bulb has more resistance than a 200W bulb, which is also true. According to the formula P = V^2 / R, for the same voltage, the bulb with higher power (200W) will have lower resistance than the bulb with lower power (100W). Therefore, both the assertion and the reason are true, and the reason correctly explains the assertion.

Assertion and reason type question: Assertion and reason are given in following questions each question has four options one of them is correct select it. Assertion: Aseries combination of cells is used when their internal resistance is much smaller than the external resistance. Reason: It follows from the relation $I = {nE \over R+n} $ Where the symbols have their standard meaning.

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Explanation

Both assertion and reason are true, and the reason correctly explains the assertion. In a series combination of cells, the total internal resistance is the sum of all the internal resistances, which is small compared to the external resistance. The given current equation $I = \frac{nE}{R+n}$ (where $n$ is the number of cells, $E$ is the emf of each cell, $R$ is the external resistance, and $n$ is the total internal resistance) shows that the current is primarily dependent on the external resistance when internal resistance is much smaller.

Assertion and reason type question: Assertion and reason are given in following questions each question has four options one of them is correct select it. Assertion: In balanced standard wheastone bridge, $ R_AC ={(P + Q) (R + S) \over (P + Q + R + S)}$ Reason: This is because B and D are at the same potential.

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Particle A and B have electric charge + q and + 4 q. Both have mass m. If both are allowed to fall under the same p.d., ratio of velocities vA /vB =

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Explanation

$ W = {1 \over 2} mv^2 = q V $ $ \therefore v = \sqrt {2qV/m} $ $ \therefore {V_A \over V_B} = \sqrt {q_A \over q_B} = \sqrt { q \over 4q} = 1/2 $ $ \therefore { V_A \over V_B } = 1:2 $

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