An electron is accelerated under a potential difference of 64 V, the de Broglie wave length associated with electron is .......... ... $A ^ \circ $ (Use charge of electon = 1.6 \times 10^{-19} ,C = 9.1 \times 10^{-31} Kg , mass of electron h = 6.623\times 10 ^ {-34} J.sec ) $
$ \lambda = { 12.27 \over \sqrt v } $ $ = { 12.27 \over \sqrt {64} } = { 12.27 \over 8} =1.553 $ $ \therefore \lambda = 1.534 A ^\circ $