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An electron is accelerated under a potential difference of 64 V, the de Broglie wave length associated with electron is .......... ... $A ^ \circ $ (Use charge of electon = 1.6 \times 10^{-19} ,C = 9.1 \times 10^{-31} Kg , mass of electron h = 6.623\times 10 ^ {-34} J.sec ) $

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Explanation

$ \lambda = { 12.27 \over \sqrt v } $ $ = { 12.27 \over \sqrt {64} } = { 12.27 \over 8} =1.553 $ $ \therefore \lambda = 1.534 A ^\circ $

A $\alpha $ particle and proton has same K.E. The ratio of de Broglie wavelength of a $ \alpha $ particle and proton is....

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Explanation

$ K = { p^2 \over 2m } $ $ \therefore p = \sqrt {2Km} $ $ \lambda = h/p = h / \sqrt{2Km} $ $ \therefore \lambda \alpha { 1 \over \sqrt m } $ $ \therefore { \lambda_\alpha \over \lambda_p } = \sqrt{m_p \over m_x} = \sqrt { 1/4} $ $ \therefore { \lambda_\alpha \over \lambda_p } = { 1 \over 2 } $

If $\alpha $ - particle and proton have same velocities, the ratio of de Broglie wavelength of $ \alpha $ -particle and proton is ....

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If $ \alpha $ - particle and proton are accelerated through the same potential difference, then the ratio of de Brogile wavelength of $ \alpha $- particle and proton is ........

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Explanation

$ K = vq $ $ { 1 \over 2 } mv^2 = Vq , m^2 v^2 = 2Vqm $ $ \therefore mv = \sqrt { 2Vqm} $ $ \lambda = { h \over mv } = { h \over \sqrt { 2Vqm } } $ $ \therefore \lambda \alpha { 1 \over \sqrt { qm } }$ $ \therefore { \lambda_\alpha \over \lambda_p} = \sqrt { q_p m_p \over q_\alpha m_\alpha } = \sqrt { em_p \over 2e \times 4m_p } = \sqrt { 1 \over 8} $ $ \therefore {\lambda_\alpha \over \lambda_p } = { 1 \over 2 \sqrt 2 } $

Read the paragraph carefully and select the proper choice from given multiple choices. According to Einstein whena photon of light of frequeny f or wavelength $ \lambda $ is incident on a photo sensitive metal surface of work function $ \phi $ . Where $ \phi < hf $ (here h is Plank's constant) then the emission of photo-electronss place takes place. The maximum K.E. of emitted photo electrons is given by $K_max = hf-\phi $. If the therehold frequency of metal is $ f_0$ then $ hf_0 = \phi $ . (ii) Stopping potential of emitted photo-electron is =........... V.

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Matching type questions : (Match, Column-I and Column-II property)

Column-I

(A) Planck's theory of quanta

(B) Einstein's theory of quanta.

(C) Bohr's stationary orbit

(D) D-Broglie waves

Column-II

(p) Light energy= hv

(q) Angular momentumofelectron in anorbit

(r) Oscillator energies

 (s) Electron microscope

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Explanation

Let's match the concepts from Column I with their corresponding properties in Column II:

(A) Planck's theory of quanta: This theory relates to the quantization of oscillator energies, where energy is given by discrete packets called quanta (r).

(B) Einstein's theory of quanta: This theory is related to the photoelectric effect, where light energy is given by hv, indicating that light consists of packets of energy called photons (p).

(C) Bohr's stationary orbit: Bohr's model postulates that electrons revolve in specific orbits with quantized angular momentum (q).

(D) D-Broglie waves: D-Broglie hypothesized that particles like electrons exhibit wave-like properties, which is crucial in the functioning of devices like electron microscopes (s).

So the correct matching is: (A-r) (B-p) (C-q) (D-s).

Matching type questions : (Match, Column-I and Column-II property) Column-I (A) Particle nature of light (B) Wave nature of light (C) Wave nature of slow moving electrons (D) Wave nature of fast moving electrons Column-II (p) Davisson and Germer (q) G. P. Thomson (r) Max. Planck (s) Muygen

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Matching type questions : (Match, Column-I and Column-II property) Column-I (I) Quantisation of charge (II) Wave nature of light (III) Dualnature of matter (IV) Particle nature of light Column-II (P) Diffraction of light (Q) de Broglie hypothesis (R) Photo-electric effect (S) Milikan's drop experiment

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Explanation

Let's match the concepts from Column I with their corresponding properties in Column II:

(I) Quantisation of charge: This is demonstrated by Milikan's oil drop experiment, which measured the charge of electrons (S).

(II) Wave nature of light: This is demonstrated by diffraction and interference experiments (P).

(III) Dual nature of matter: This is proposed by the de Broglie hypothesis, which states that particles exhibit both wave and particle properties (Q).

(IV) Particle nature of light: This is explained by the photoelectric effect, where light is shown to have particle-like properties (R).

So the correct matching is: I-S, II-P, III-Q, IV-R.

Matching type questions : (Match, Column-I and Column-II property) Column-II Column-I (I) Energy of photon of wavelength $ \lambda $ is (II) The be Broglie wavelength associated with
particle ofmomentum P is (III) Mass of photon in motion is (IV) The velocity of photon of energy E and P is Column-II (P) E/p (Q) $ hf / c^2 $ (R) $ hc / \lambda $ (S) h /p

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Explanation

To solve this matching question, use the following formulas:

  1. Energy of photon of wavelength \( \lambda \) is given by \( E = \frac{hc}{\lambda} \). So, I matches with R.
  2. The de Broglie wavelength associated with a particle of momentum \( P \) is given by \( \lambda = \frac{h}{p} \). So, II matches with S.
  3. Mass of photon in motion is given by \( m = \frac{hf}{c^2} \). So, III matches with Q.
  4. The velocity of photon of energy \( E \) and momentum \( P \) is given by \( v = \frac{E}{p} \). So, IV matches with P.

Therefore, the correct matching is: I- R, II- S, III- Q, IV - P.

Two different loops are concentric & lie in the same plane. The current in outer loop is clockwise & increasing withtime. The induced current in the inner loop then, is

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Explanation

According to Lenz's law, the direction of the induced current is such that it opposes the change in magnetic flux that caused it. Since the current in the outer loop is increasing clockwise, the magnetic field due to this current is increasing out of the plane. To oppose this increase, the induced current in the inner loop must create a magnetic field into the plane. Hence, the induced current in the inner loop must be counterclockwise.

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