NEET Practice Questions (MCQs) with Answers & Solutions

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The behaviour of Ge as semi-conductor is due to width of :

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Explanation

The behavior of germanium (Ge) as a semiconductor is due to the width of the forbidden band being small and narrow. In semiconductors, the forbidden band (also called the band gap) is small enough to allow electrons to jump from the valence band to the conduction band at room temperature, thus allowing the material to conduct electricity.

Which of the following is not the advantage of PN junction diode over tube valve ?

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Explanation

The advantage of a PN junction diode over a tube valve that is not true is 'Unlimited life'. While PN junction diodes do have many advantages such as no warming-up time, large efficiency, and low power consumption, they do not have an unlimited lifespan. They can degrade over time due to factors such as heat and electrical stress.

A current gain for a transistor working as CB amplifier is 0.90. If emitter current is 10 mA, then base current is

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Explanation

$ \alpha = { I_c \over I_e } $ $ \therefore I_c = \alpha I_E = 9mA $ $ I_B = I_E -I_C = 10-9 =1 mA $

For a transistor $ { I_c \over I_E } =0.96 $, then CE current gain is :

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Explanation

$ \beta = { \alpha \over 1 -\alpha } $

At 0 K temp, a N - type semi-conductor

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Explanation

At 0 K temperature, an N-type semiconductor does not have any charge carriers. At absolute zero, all the electrons in the semiconductor are bound to atoms and there is no thermal energy to excite electrons into the conduction band. Hence, there are no free charge carriers (electrons or holes) available for conduction.

In Si-crystal, impurity donor atom have valency.

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Explanation

In a silicon crystal, an impurity donor atom typically has a valency of 5. Such atoms are called pentavalent impurities and they donate extra electrons to the silicon crystal, making them n-type semiconductors. Examples of pentavalent impurities include phosphorus (P), arsenic (As), and antimony (Sb).

A N-P-N transistor conducts when collector is______ and emitter is_____ with respect to base.

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A full wave rectifier is operating at 50Hz, 220V the fundamental frequency of ripple will be

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Explanation

A full wave rectifier converts both halves of the AC input signal into pulsating DC. Therefore, the ripple frequency of a full wave rectifier is twice the frequency of the AC supply. Given the AC supply frequency is 50Hz, the ripple frequency will be 2 * 50Hz = 100Hz.

Reverse bias applied on a junction diode :

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Explanation

In a junction diode, when reverse bias is applied, the potential barrier increases. This is because the negative terminal of the battery is connected to the n-side and the positive terminal to the p-side, resulting in an increase in the depletion region and a higher potential barrier.

For a transistor, in a common base configuration the alternating current gain $ \alpha $ is given by :

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Explanation

In a common base configuration of a transistor, the alternating current gain (α) is defined as the ratio of the change in collector current (ΔI_C) to the change in emitter current (ΔI_E), with the collector voltage (V_c) held constant. Thus, $$ ext{α} = rac{ΔI_C}{ΔI_E} igg|_{V_c = const} $$.

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