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A centigrade and a Fahrenhait thermometer one dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers 140°. What is the fall in temperatures as registered by the centigrade thermometer ?
$ { \triangle T_C \over 100 } = { \triangle T_F \over 180 } $
100 g ice at 0°C placed in 100 g water at 100°C. The final temperature of the mixture will be.......... (Latent heat of ice is 80 Cal/g, and specific heat of water is 1 Cal/g C°)
Let temperature of mixture = T $ \therfore $ Heat absorbed by ice = Heat lost by water $ \therefore $ Heat required to melt ice + heat required to acquire Temperature T of water of ice = Heat lost by water $\therefore $ mL + mc (T - 0) = mc (100 - T)
On a hot day at Ahmedabad a trucker loaded 37,000 L of diesel fuel. He delivered the disel at Shrinagar (Kashmir) Where the temperature was lower then that of Ahmedabad by 23 k. How many liters did he deliver ?For diesel $ \gamma = 3 \alpha = 9.50 \times 10^{-4} C° $ (Neglect the thermal expansion / Contration of steel tank of the trunk)
$ V = 37000 L \triangle T = 27K$. As temperature decreases in volume. $ \triangle V =3 \alpha V \triangle T= 9.5 \times 10^{-4} \times \times 37000 \times 23 $ = 808 L decreases $ \therefore $ Diesel supplied to shrinagar = 37000 - 808 = 36192L = 36190L
For which value of the temperature will the values of Fahrenhit scale and Kelvin scale be equal ?
$T_F = {9 \over 15 } [T_K -273 ] + 32$
The temperautre of equal masses of three different liquids x, y, z are $ 12 ^\circ C , 19 ^\circ C and 28 ^\circ C$ respectively. The temperature when X and Y are mixed is $ 16 ^\circ C$ and when Yand Z are mixed is $23 ^\circ C$ . what is the temperature when X and Z are mixed ?
When X and Y are mixed heat lost by Y = Heat gained by X $ms_y (19-16) = ms_X(16-12)$
Similarly when Y and Z are mixed $ ms_y (23-19) = ms_z (28-23)$ Mixing x and z yields, $ms_X(T -12) = ms_z (28 -T)$ Mixing X and Z yields. Solved all equations
Two liquids of equal volume are throughly mixed. If their specific heat are $C_1, C_2$, temperatures $ \theta_1, \theta_ 2$ and densities $d_1, d_2$ respectively. What is the final temperature of the mixture ?
$ mC_1 ( \theta_1 - \theta_e ) = m C_2 ( \theta_e - \theta_2 ) $ $ Vd_1C_1 ( \theta_1 - \theta_e) = Vd_2 C_2( \theta_e - \theta_2) $ $ \Rightarrow d_1 c_1 \theta_1 -(d_1c_1) \theta_e = (d_2 c_2) \theta_e - d_2 c_2 \theta_2 $
In a simple metre-bridge circuit, the both gaps are bridge by coils P and Q having the smaller resistance. A balance is obtained when the jockey key makes contact at a point of the bridge wire 40 cm from the P end. On shunting the coil Q with a resistance of $50\Omega $ the balance point is moved through 10 cm. What are the resistance of P and Q ?
Case 1 : P/40 = Q /40 ....(1) On shunting Q with 50 ï— the resistance of the armcontaining Q comesdown, so length also must shorten to keep the ratio same. $ \Rightarrow { P \over (40 + 10 ) } = { \left( 50 Q \over 50+Q \right) \over (60 -10) } \Rightarrow P = { 50 \over 50+Q } $....(2) Solving (1) and (2) we get $ P = {50 \over 3 } \Omega and { 50 \over 2 } \Omega $
What is the resistance of an open key ?
$ R = {V \over I } i.e. I = 0 \Rightarrow R = infinite $
What is the unit of temperature coefficient of resistance ?
Knowledge base
Which one of the following is not Ohm's law ? (J = current density, E = Electric field, $ \rho $ = resistivity and $ \sigma $ conductivity)
I = V / R is obviously Ohm's law. $ \Rightarrow = \sigma E $ is still another form for Ohm's law.
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