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A moving coil galvanometer has 150 equal divisions, Hs current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each divisions reads1 V. What will be the resistance in ohms needed to be connected in series with the coil ?
$ I_g = { V \over (R + G) } $
A galvonometer of resistance$ 200 \Omega $ gives full scale deflection for a current of $10^{–3} A$. To convert it into an anmeter capable of measuring upto 1A. What resistance should be connected inparallel with it ?
$ S = \left( I_g \over I - I_g \right) G $
A galvanometer with resistance $100 \Omega $ is converted into an ammeter with a resistance of 0.1 . The galvanometer shows full scale deflection with current of $100 \mu A$. Then what will be the minimum current in the circuit for fall scale deflection of galvanometer ?
The range of a galvanometer of resistance G ohm is V volt. The resistance required to be connected in series with it in order to convert it into voltmeter of range nV volt will be........
$ nV = Ig (G +R) $
The seave of a galvanometer of resistance $100 \Omega $ contains 25 divisions. It gives a deflection of 1 division on passing a current of $ 4 \times 10^{-4} A$. The resistance in ohm to be added to it. so that it may become a voltmeter of range 2.5 V is .................
For full scale deflection , Ig = nk $ R = { V \over Ig } -G $
A galvanometer of resistance $200 \Omega $ gives full scale deflection with 15 milli-aupere current. In order to convert it into a 15V range voltmeter. What is the value of resistance connected in series ?
$ R = \left({ V \over Ig } \right) -G $
A galvanometer, having a resistance of $ 50 \Omega $ , gives a fall scale deflection for a current of 0.05A.The length in metre of a resistance wire of are of cross-secion $ 2.97 \times 10^{-2} cm^{2} $ that can be used to convertt the galvanometer into an ammeter which can read a maximum of 5A current is (specific resistance of wire = $ 5 \times 10^{-7} \Omega m$ )
$ (I -Ig) S = IgG$ $ R = \rho (l / A) $
An ammeter of range 5A is to be converted into an ammeter of range 10V. If the resistance of ammeter be 0.1 ,then what resistance should be connected in series with it ?
$ R = \left ( {V \over I } - G \right) $
What is the relation between figure of merit (k) and current sensitivity ($S_I$) ?
$ S_I = { I \over \theta } where as, k ={ \theta \over I } \Rightarrow S_1 = { 1 \over k } $
One microammeter has a resistance of $100 \Omega$ and a full scale range of $ 50 \mu A$ . It can be used as a voltmeter or as a higher range ammeter provided a resistance is added to it. Pick the correct range and resistance combinations (s).
$ I_g = { V \over (R+G) } $
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