NEET Practice Questions (MCQs) with Answers & Solutions

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The period of a satellite in cirular orbit around a planet is independent of

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Explanation

The period (T) of a satellite in a circular orbit is given by $T = 2 rac{ ext{ extpi}}{ u}$ where $ u$ is the orbital velocity. Using the relationship for orbital velocity $ u = rac{GM}{r}$, we derive $T = 2 ext{ extpi} rac{r^{3/2}}{ ext{ extpi} rac{GM}{r}}$. Here, the period of the satellite depends on the radius of the orbit and the mass of the planet, but not on the mass of the satellite. Therefore, the period of the satellite is independent of the mass of the satellite.

Two satellites A and B go round a planet p in circular orbits having radii 4 R and R respectively if the speed of the satellite A is 3V, the speed if satellite B will be

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Explanation

$ \upsilon = \sqrt { GM \over R } \Rightarrow { V_A \over V_B} = \sqrt { R_E \over R_A } = \sqrt { R \over 4R } = { 1 \over 2 } $ $ \therefore { V_A \over V_B } = {3V \over VA } $ $ V_E = 6V $

A small satellite is revolving near earth’s surface. Its orbital velocity will be nearly= ………………..$kms^{–1}$.

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Explanation

The orbital velocity of a satellite near Earth's surface can be calculated using $ u = rac{GM}{r}$, where G is the gravitational constant, M is the mass of the Earth, and r is the radius of the Earth. For Earth, this velocity is approximately 8 km/s. Therefore, the correct option is 8 km/s.

A satellite revolves around the earth in an elliptical orbit. Its speed

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Explanation

The speed of a satellite in an elliptical orbit is greatest when it is closest to the Earth due to the conservation of angular momentum. This point is known as the perigee. In an elliptical orbit, the gravitational force does more work on the satellite as it moves closer to the Earth, increasing its speed.

If the height of a satellite from the earth is negligible in comparison of the radius of the earth R, the orbital velocity of the satellite is ............

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Explanation

If the height of the satellite is negligible compared to the radius of the Earth, the orbital velocity 'v' is given by the formula: \[ v = \\sqrt{gR} \] where 'g' is the acceleration due to gravity and 'R' is the radius of the Earth.

A satellite is moving around the earth with speed v in a circular orbit of radius r. If the orbit radius is decreasd by 1% its speed will

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Explanation

$ \upsilon \alpha {1 \over \sqrt r } $ % increase in speed = 1\2 % decrease in radius = 1/2 (1%) = 0.5 %

Orbital velocity of an artifiicial satellite does not depend upon

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Explanation

$ \upsilon = \sqrt { GM \over r } $

Which one of follwoing sttements regarding artificial satellite of earth is incorrect

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Explanation

The orbital velocity of a satellite does not depend on its mass. It depends only on the mass of the Earth and the radius of the orbit. Hence, the statement 'The orbital velocity depends on the mass of the satellite' is incorrect.

The weight of an astronuat, in an artificial satellite revolving around the earth is

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Explanation

The weight of an astronaut in an artificial satellite revolving around the Earth is zero. This is because the astronaut and the satellite are both in free fall towards the Earth, creating a condition of apparent weightlessness. The gravitational force provides the centripetal force needed to keep the satellite in orbit, but since the astronaut is also in free fall, they do not experience this force as weight.

The distance of a geo-stationary satellite from the center of the earth (Radius R= 6400km) is nearest to

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Explanation

6R from the surface of earth and 7R from the center

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