NEET Practice Questions (MCQs) with Answers & Solutions

Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Register free for language, difficulty & keyword filters

To locate the position of the particle we need ...

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

To locate the position of a particle, we need a frame of reference. A frame of reference is a coordinate system that allows us to specify the position of a particle in space by giving its coordinates relative to some origin.

Two pulley arrangements of figure given are identical. The mass of the rope is negligible. In fig (a), the mass m is lifted by attaching a mass 2m to the other end of the rope. In fig (b), m is lifted up by pulling the other end of the rope with a constant downward force F = 2mg. The acceleration of m in the two cases are respectively

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

A car goes from one end to the other end of a semicircular path of diameter ‘d’.
Find the ratio between path legth and displacement.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The path length of a car moving along a semicircular path of diameter 'd' is equal to half the circumference of a circle, which is $\pi d / 2$. The displacement is the straight line distance between the start and end points, which is 'd'. Therefore, the ratio between the path length and displacement is $(\pi d / 2) / d = \pi / 2$.

The ratio of pathlength and the respective time interval is

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The ratio of path length to the respective time interval is called mean speed. Mean speed is defined as the total distance traveled divided by the total time taken.

A car covers one third part of its straight path with speed $V_1$ and the rest with speed $V_2$. What is its average speed ?

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Rohit completes a semicircular path of radius R in 10 seconds. Calculate average speed and average velocity in $ms^{–1}$.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

To calculate the average speed and average velocity for Rohit completing a semicircular path of radius R in 10 seconds, we start with the average speed. The average speed is the total distance traveled divided by the total time taken. For a semicircle, the distance is half the circumference of a full circle, which is $ rac{1}{2} imes 2 ext{Ï€}R = ext{Ï€}R$. Therefore, the average speed is $$ ext{Average speed} = rac{ ext{Ï€}R}{10}.$$ For the average velocity, we consider the straight-line displacement from the start to the end of the semicircle, which is the diameter of the circle, or $2R$. Therefore, the average velocity is $$ ext{Average velocity} = rac{2R}{10}.$$ This matches the option 'o3'.

A particle moves 4m in the south direction. Then it moves 3m in the west direction. The time taken by the particle is 2 second. What is the ratio between average speed and average velocity ?

You've reached today's free limit of 20 questions. Log in to keep practising for free.

What does the speedometer measure kept in motorbike ?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

A speedometer measures the instantaneous speed of a vehicle. Instantaneous speed is the speed of an object at a particular moment in time. It does not measure average speed or velocity. Hence, the correct option is o3: instantaneous speed.

A particle is thrown in upward direction with initial velocity $V_0$. It crosses point P at height h at time $t_1$ and $t_2$ so $t_1 t_2$ =

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ h = V_0 t - {1 \over 2 } gt^2 $ $ \therefore {1 \over 2 } gt^2 - V_0 t + h = 0 $ $ \therefore t^2 + { 2V_0 \over g } - { 2h \over g } = 0 $ There are two real values of t .

Slope of the velocity-time graph gives............ of a moving body.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The slope of a velocity-time graph represents the acceleration of the moving body. This is because acceleration is defined as the rate of change of velocity with respect to time. Therefore, the slope of the velocity-time graph is the acceleration. Hence, the correct option is o2: acceleration.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.