Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Motion of a particle is described by an equation $ \upsilon = (A + y ) ^{1 /2 } $
where v, y and A are velocity distance and a constant respectively. Find the
acceleratrion of the particle.
$ V = ( A + y ) ^{1 /2 } $ $ \therefore a = { dv \over dt } = { dv \over dy } . { dy \over dt } $
The minumum distance in which a car can be stopped is x. The velocity of the
car is V. If the velocity is 2V then find the stopping distance.
$ s = { v^2 \over 2 a } $
A goods train is moving with constant acceleration. when engine passes through a signal its speed is U. Midpoint of the train passes the signal with speed V. What will be the speed of the last wagon ?
For a train moving with constant acceleration, the speed of the last wagon can be found using the kinematic equations. Given that the speed of the engine when it passes the signal is U and the speed at the midpoint is V, we can use the relationship between these speeds to find the speed of the last wagon. The correct formula is $ ext{speed} = \\sqrt{2V^2 - U^2} $, which matches option o4.
The area under acceleration versus time graph for any time interval represents
The area under an acceleration vs. time graph represents the change in velocity over a given time interval. This is derived from the definition of acceleration, which is the rate of change of velocity. Therefore, integrating acceleration with respect to time gives the change in velocity. Hence, option o3 is correct.
Radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is
For perfectly reflecting surface, momentum transferred = 
An object moves in x - y plane. Equations for displacement in x and y direction are x = 3sin2t and y = 3cos2t Speed of the particle is
The equations given for displacement are x = 3sin(2t) and y = 3cos(2t). These represent parametric equations of a circle with radius 3. The speed of a particle moving in a circle with constant radius and angular speed is constant. Thus, the speed is constant and non-zero. Hence, option o2 is correct.
To introduce a vector quantity ....
A vector quantity is defined by having both a magnitude and a direction. For example, velocity is a vector because it specifies how fast something is moving (magnitude) and in which direction. Therefore, to introduce a vector quantity, it needs both magnitude and direction.
Which from the following is a scalar ?
Electric current is a scalar quantity. Unlike vectors, scalar quantities have only magnitude and no direction. Electric current is described by its magnitude, which is the rate of flow of charge through a conductor, but it does not have a specific direction in the sense that a vector does.
$ \vec P and \vec Q $ are equal vectors what from the followings is true.
If two vectors $ \\vec{P} and \\vec{Q} $ are equal, it means they have both the same magnitude and the same direction. Therefore, $ \\vec{P} and \\vec{Q} $ are parallel to each other.
$ \vec P = \vec Q $ is true , if
For two vectors \( \vec{P} \) and \( \vec{Q} \) to be equal, they must have both equal magnitudes and the same direction. This is because vectors are defined by both their magnitude and direction. Therefore, \( \vec{P} = \vec{Q} \) is true if and only if their magnitudes are equal and they are in the same direction.
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.