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At a given temperature the rms velocity of molecules of the gas is

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Explanation

$ \nu _{rms } = \sqrt {3RT \over M_o } \Rightarrow \nu _{rms} \alpha { 1 \over \sqrt {M_o} } $

According to the kinetic theroy of gases the r.m.s velocity of gas molecules is directly proportional to

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Explanation

$ \nu_{rms } \alpha \sqrt T $

The speeds of 5 molecules of a gas (in arbitrary units) are as follows: 2, 3, 4, 5, 6, The root mean square speed for these molecules is

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Explanation

$ \nu_{rms} = \sqrt { \nu_1^2 + \nu_2^2 + \nu_3^2 + \nu_4^2 + \nu_5^2 \over 5 } = 4.24 $

To what temperature should the hydrogen at room temperature ($ 27 ^\circ C$ ) be heated at constant pressure so that the rms velocity of its molecule becomes double of its previous value

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Explanation

$ \nu_{rms } \alpha \sqrt T \Rightarrow { (\nu_{rms})_2 \over (\nu_{rms})_1} = \sqrt {T_2 \over T_1} $

Root mean square velocity of a molecule is $ \nu $ at pressure P. If pressure is increased two times, then the rms velocity becomes

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Explanation

rms velocity does not depend on pressure.

The rms speed of gas molecules is given by

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Explanation

$ \nu _{rms } = \sqrt { 3RT \over M_o} = \sqrt {3} \sqrt { RT \over M_o } = 1.73 \sqrt { RT \over M_o} $

A sample of gas is at $ 0 ^\circ C$ . To what temperature it must be raised in order to double the rms speed of molecule.

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Explanation

$ \nu_{rms} \alpha \sqrt T $ To double the rms speed temperature should be made four times i.e. $ \therefore T_2 = 4 T_1 $

If the ratio of vapour density for hydrogen and oxygen is 1/ 16 , then under constant pressure the ratio of their rms velocities will be

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Explanation

$ \nu _ {rms} =\sqrt { 3P \over \rho } \Rightarrow { \nu_1 \over \nu_2 } = \sqrt { \rho_2 \over \rho_1} = \sqrt { 16 \over 1} = 4:1 $

The molecules of a given mass of a gas have a rms velocity of 200 m /s at $ 27 ^\circ C$ and $ 1.0 \times 10^5 Nm^{-2} $ pressure when the temperature is $ 127 ^\circ C$ and pressure is $ 0.5 \times 10^5 Nm^{-2} $ , the rms velocity in m s will be

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Explanation

rms velocity doesn't depend on pressure, it depends upon temperature only $ \nu_{rms} = \sqrt { 3RT \over Mo } \Rightarrow \nu_{rms} \alpha \sqrt T $ $ \therefore T \alpha \nu_{rms}^2 \Rightarrow { \nu_1 \over \nu_2 } = \sqrt { T_1 \over T_2 } $

If the molecular weight of two gases are $ M_1$ and $M_2$ , then at a given temperature the ratio of root mean square velocity $ \nu _1 $ and $ \nu _2 $ will be

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Explanation

$ \nu_{rms} = \sqrt { 3RT \over Mo } \Rightarrow \nu_1 \alpha \sqrt { 1 \over M_1 } and \nu_2 \alpha \sqrt { 1 \over M_2} \Rightarrow { \nu_1 \over \nu_2 } = \sqrt { M_2 \over M_1 } $

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