The no. of images formed between two parallel plane mirror are
$ no.of image = { 360 ^\circ \over \theta} = { 360 ^ \circ \over 0^\circ } = \infty $
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The no. of images formed between two parallel plane mirror are
$ no.of image = { 360 ^\circ \over \theta} = { 360 ^ \circ \over 0^\circ } = \infty $
To get five images of a single object one should have two plane mirrors at an angle of.........
To determine the angle between two plane mirrors to get a specific number of images, we can use the formula: \( n = \frac{360}{\theta} - 1 \), where \( n \) is the number of images formed and \( \theta \) is the angle between the mirrors. For five images, we set \( n = 5 \) and solve for \( \theta \): \( 5 = \frac{360}{\theta} - 1 \) \( 6 = \frac{360}{\theta} \) \( \theta = \frac{360}{6} = 60^\circ \). So the correct answer is 72 degrees.
If a glass rod is immersed in a liquid of the same refractive index, then it will
When a glass rod is immersed in a liquid with the same refractive index, light passes through both materials without bending or reflecting at the boundary, making the rod virtually invisible. This is because there is no change in the speed of light and no refraction occurs at the interface.
For four different transparent medium $ n_{41} \times n_{32} \times n_{21} =$
The relationship between the refractive indices of different media follows the principle of reversibility of light. For four different transparent media, the product of the refractive indices \( n_{41} \times n_{32} \times n_{21} \) is the same as the reciprocal of \( n_{14} \) because \( n_{ij} = \frac{1}{n_{ji}} \). Therefore, \( n_{41} \times n_{32} \times n_{21} = \frac{1}{n_{14}} \).
A Plane mirror produces a magnification of
A plane mirror always produces an image that is virtual, erect, and of the same size as the object. Therefore, the magnification produced by a plane mirror is +1. This means the size of the image is equal to the size of the object.
A convex lens forms a real image of an object for it s two different positons on a screen if hight of the image in both cases be 16 cm and 4 cm then height of the object is ..........cm
$ use \;ho = \sqrt {h_1 h_2 }$
Two thin lenses of focal lengths $ f_1 and f_2 $ are coaxially placed in contact with each other then, the power of combination is ............
When two thin lenses of focal lengths \( f_1 \) and \( f_2 \) are placed in contact, the power of the combination (P) is given by the sum of the powers of the individual lenses. Power is the reciprocal of the focal length (in meters). Therefore, \( P = rac{1}{f_1} + rac{1}{f_2} = rac{f_1 + f_2}{f_1 f_2} \).
If thin prism of $ 5 ^\circ $ gives a deviation of $ 2 ^\circ $ then the refractive index of material of prism is
It is difficult to see through the fog because
Light is scattered by the droplets in the fog. This scattering of light causes multiple reflections and deflections, making it difficult for our eyes to see through the fog clearly. This phenomenon is known as Rayleigh scattering.
Read the following quetions and choose if_ Assertion : Focal lengh of a lens for
red colour is smaller than its focal length for violet colour
Reason : is because $n_r \gt n_v $
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