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An open organ pipe has fundamental frequency 100 hz. What frequency will be produced if its one end is closed?
When one end is closed $f_1 = {100 \over 2 } = 50 Hz $ $ f_2 = 3f_1 =150 Hz , f_3 = 5f_1 =250Hz and so on...$
A closed organ pipe has fundamental frequency 100 hz. What frequencies will be produced if its other end is also opened?
When other end of pipe is opened, its fundamental frequency becomes 200Hz. The overtone have frequencies 400, 600, 800 Hz..
A column of air of length 50 cm resonates with a stretched string of length 40 cm. The length of the same air column which will resonate with 60 cm of the same string at the same tension is ……..
$ As , { l_2 \over 2l }= { l_2' \over l_1'} \Rightarrow { 60 \over 40 } = { l_2' \over 50 } = l_2' = 75cm $
Two forks A and B when sounded together produce 4 beats/s. The fork A is in unison with 30 cm length of a sonometer wire and B is in unison with 25 cm length of the same wire at the same tension. The frequencies of the fork are
$ { f_2 \over f_1 } = { l_2 \over l_1 } = { 25 \over 30 } = { 5 \over 6 } $ $ f_2 - f_1 = 4 on solving we get f_2 = 24 Hz $ $ \therefore f_1 = 20 Hz $
A tuning fork of frequency 200 hz is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by 1 % is
$ { f_2 \over f_1 } = \sqrt { 101 \over 100 } = \left( 1 + { 1 \over 100 } \right) ^ {1 /2 } = 1 + {1 /200} $ $ \therefore f_2 = f_1 + { f_1 \over 200} $ $ \therefore numbers of be ab s^{-1} = f_2 -f_1 = {f_1 \over 200} = 1 $
A bus is moving with a velocity of 5 m/s towards a huge wall. The driver sounds a horn of frequency 165 hz. If the speed of sound in air is 335 m/s, the number of beats heard per second by the passengers in the bus will be …….
$ { f_L \over f_S} = { \nu + \nu_L \over \nu + \nu_S } $ $ here \nu_L = + 5 ms^{-1} , \nu_s = -5 ms^{-1} , f_s = 165 Hz $ $ \therefore f_L =170 Hz \therefore Number of be ab s^{-1} = 170 -165 = 5 $
A vehicle with a horn of frequency n is moving with a velocity of 30 m/s in a direction perpendicular to the straight line joining the observer and the vehicle. The observer perceives the sound to havea frequency $( n + n_1 )$. If the sound velocity in air is 300 m/s, then
As the source is moving perpendicular to straight line joining the observer and source, (as if moving along a circle), apparent frequency is not affected $n_1 = 0$
A sonometer wire supports a 4 kg load and vibrates in fundamental mode with a tuning fork of frequency 416 hz. The length of the wire between the bridges is now doubled. In order to maintain fundamental mode, the load should be changed to …….
At a displacement antinode, a pressure node is present. Since pressure does not change at its node, nor does density.
In brass, the velocity of a longitudinal wave is 100 times the velocity of a transverse wave. If $ Y = 1 \times 10^{11} N/m^2$, then stress in the wire is …………
For a sonometer fundamental $ f = {1 \over 22} \sqrt { T \over \mu } $ To maintain the fundamental mode, in doubling the length, tension must be quadrupled
A car blowing its horn at 480 hz moves towards a high wall at a speed of 20 m/s. If the speed of sound is 340 m/s, the frequency of the reflected sound heard by the driver sitting in the car will be closest to hz.
If the length of the wire between the two bridges is l , then the frequency of vibration is $ n = { 1 \over 21 } \sqrt { T \over m } = { 1 \over 21 } \sqrt { T \over \pi r^2 d $ If the length and diameter of the wire are doubled keeping the tension same, then new fundamental frequency will be n/4
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