The resistance $ R = { V \over I } $ where $ V = 100 \pm 5 volts $ and $ I = 10 \pm 0.3 amperes $ calculate the percentage error in R.
$$ Resistance R = { V \over I} $$ ${ \triangle R \over R } = { \triangle V \over V } + { \triangle I \over I } $ $ { \triangle R \over R } = { 5 \over 100} + { 0.3 \over 10 } $ $ { \triangle R \over R } = { 8 \over 100} $ $ { \triangle R \over R } \% = 8 \% $