The value of poisson's ratio lies between........
$ y = 3k (1-2 \sigma); y = 2n (1 + \sigma) $ $ For Y=0 we get 1 -2 \sigma = 0 also 1 + \sigma = 0 $ $ \Rightarrow \sigma lies between $
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The value of poisson's ratio lies between........
$ y = 3k (1-2 \sigma); y = 2n (1 + \sigma) $ $ For Y=0 we get 1 -2 \sigma = 0 also 1 + \sigma = 0 $ $ \Rightarrow \sigma lies between $
If the young's modulus of the material is 3 times its modulus of rigidity. Then what will be its volume elasticity ?
$ y = 2n ( 1 + \sigma) \rightarrow 3n = 2n ( 1 + \sigma) \Rightarrow \sigma = {3 \over 2 } -1 = {1 \over 2 } $ Now, substituting the value of $ \sigma $ in the following expression $ \Rightarrow k = { y \over 3 ( 1 - 2 \sigma) }= \infty $
For a given material the Young's modulus is 2.4 times that of rigidity modulus. What is its poisson's ratio ?
$ Y = 2n ( 1 + \sigma ) $
The lower surface of a cube is fixed. On its upper surface is applied at an angle of $ 30 ^\circ $ from its surface. What will be the change of the type ?
There will be both shear stress and normal stress.
The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of $ 30 ^\circ $ . Then what is the angle of shear ?
Angle of shear $ \phi = { r \theta \over L } = { 4 \times 10^{-1} \over 100 \times 30' } = 0.12 ' $
A 2mlong rod of radius 1 cm which is fixed from one end is gien a twist of 0.8 radians. What will be the shear strain developed ?
$ r \theta = L \phi 10^{-2} \times 0.8 = 2 \times \phi = 0.004$
Shearing stress causes change in
$ Y = 3K (1 -2 \sigma ) and Y = 2n ( 1 + \sigma) $ $ Eliminating \sigma we got Y = { 9nk \over n+3k } $
What is the relationship between Young's modulus Y, Bulk modulus k and modulus of rigidity $ \eta $ ?
Poisson's ratio varies between - 1 and 0.5
Assertion and Reason : Read the assertion and reason carefully to mark the correct option out of the option given below Assertion : The bridges are declared unsafe after a long use. Reason : Elastic strength of bridges decrease with
Ivory is more elastic than wet-clay. Hence, the ball of ivory will rise to a greater height. In fact the ball of wet day will not rise at all it will be same, what flattended permanently.
Assertion and Reason : Read the assertion and reason carefully to mark the correct option out of the option given below Assertion : Two identical solid balls, one of ivory and the other of wet clay are dropped from the same height on the floor. Both the balls will rise to same height after. Reason : Ivory and wet-clay have same elasticity.
Young's modulus of a material Y = stress /strain Here, stress force = $ {Restrating \over area }$ force As restoring force is zero. Y = 0
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