A metal ball of mass 2 kg moving with a velocity of 36 km/h has a head on collision with a stationary ball of mass 3 kg. If after the collision, the two balls move together, the loss in kinetic energy due to collision is
By low of conservation of momentum $ 2 \times 10 = (2+3) v $ $ \therefore v = 4 m/s $ Loss in K.E = $ { 1 \over 2} (2) (10)^2 - { 1 \over 2} (5) (4) ^2 $