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Compounds with high heat of formation are less stable because
Compounds with a high heat of formation are less stable because they are in an energy-rich state which leads to instability. High heat of formation indicates that a lot of energy is stored within the compound, making it prone to releasing energy and thus being less stable.
When a gas undergoes adiabatic expansion, it gets cooled due to
For a reaction to occur spontaneously
A Beckmann thermometer is used to measure
A Beckmann thermometer is specifically designed to measure small differences in temperature, often in the range of 0.01°C to 5°C. This makes it suitable for measuring low temperatures with high precision.
The calorific value of fat is ……….
The calorific value of fat is higher than that of carbohydrates and protein. This is because fats contain long chains of hydrocarbons which, when oxidized, release more energy compared to carbohydrates and proteins. Carbohydrates and proteins have approximately 4 kcal/g, while fats have about 9 kcal/g.
Which of the following processes is accompanied by an increase in entropy ?
The decomposition of $N_2O_5$ to $N_2O$ and $O_2$ is accompanied by an increase in entropy. This is because the decomposition reaction results in more molecules being produced (more moles of gas). In general, reactions that produce more gas molecules tend to have an increase in entropy.
Which of the following does not exhibit zero entropy at absolute zero
Glass does not exhibit zero entropy at absolute zero. According to the third law of thermodynamics, crystalline substances have zero entropy at absolute zero. However, glass is an amorphous solid and does not have a perfectly ordered structure, thus retaining some entropy even at absolute zero.
The favourable conditions for a spontaneous reaction are
On passing $CO_2$ gas in water, its entropy
When does the reaction occur spontaneously on the basis of the relation $ OG ^\circ = –RT/nK $ ?
The relation $ΔG^ ext{°} = -RT ext{ln} K$ indicates that for a reaction to be spontaneous, ΔG must be negative. This happens when the equilibrium constant K is greater than 1 because the natural logarithm of a number greater than 1 is positive, making $ΔG^ ext{°}$ negative.
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