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Zeigler-Natta catalyst is used for which type of reaction.

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Explanation

The Ziegler-Natta catalyst is used in the polymerization of alkenes to produce polymers like polyethylene and polypropylene. This catalyst allows for the control of the polymer structure and molecular weight.

An aqueous solution of potash Alum gives.

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Carnalite in solution in H2O shows the properties of.

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Explanation

Carnallite is a mineral composed of hydrated potassium magnesium chloride, with the formula KMgCl3·6H2O. When dissolved in water, it dissociates into its constituent ions: $K^+$, $Mg^{2+}$, and $Cl^-$. So, the correct option is $K^+, Mg^{2+}, Cl^-$. Hence, option o1 is correct.

Number of ions present in aqueous solution of $Fe_4 [Fe(CN)_6]_3 $ is

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Explanation

The compound $Fe_4[Fe(CN)_6]_3$ dissociates in water to produce 4 $Fe^{3+}$ ions and 3 $[Fe(CN)_6]^{4-}$ ions. The total number of ions in solution is 4 + 3 = 7. Therefore, the correct option is 7 ions. Hence, option o3 is correct.

How many ions are produced in aqueous solution of $[CoH_2O)_6] Cl_2$ ?

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Explanation

The compound $[Co(H_2O)_6]Cl_2$ dissociates in water to form one $[Co(H_2O)_6]^{2+}$ ion and two $Cl^-$ ions. Thus, the total number of ions produced is 1 + 2 = 3. Therefore, the correct option is 3 ions. Hence, option o2 is correct.

The formula of dichlorido bis (urea) copper (II) is ?

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Explanation

The correct formula for dichlorido bis (urea) copper (II) is $ [CuCl_2(O=C(NH_2)_2)_2] $. In this complex, the copper ion (Cu^2+) is coordinated to two chloride ions (Cl^-) and two urea molecules. This is indicated by the bis (urea) and dichlorido in the name.

Correct formula of diammine silver (I) chloride is ?

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Explanation

The correct formula for diammine silver (I) chloride is $ [Ag(NH_3)_2]Cl $. In this complex, the silver ion (Ag^+) is coordinated to two ammonia molecules (NH_3), forming the diammine complex, and there is one chloride ion (Cl^-) balancing the charge.

The formula of sodium nitroprusside ?

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Explanation

The correct formula for sodium nitroprusside is $ Na_2[Fe(CN)_5NO] $. In this complex, the iron (Fe) is in the +3 oxidation state and is coordinated to five cyanide ions (CN^-) and one nitrosyl group (NO). There are two sodium ions (Na^+) to balance the charge of the complex.

The oxidation numbers of chromium in $Na_2[CrF_4O] $ complex is ?

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Explanation

To determine the oxidation state of chromium in $Na_2[CrF_4O]$, we need to consider the charges of the other components in the complex. Sodium (Na) has an oxidation state of +1. Fluoride (F) has an oxidation state of -1, and oxygen (O) usually has an oxidation state of -2. Let the oxidation state of chromium be x. The net charge of the complex ion $[CrF_4O]^{2-}$ should be equal to -2. Therefore, the equation can be set up as follows:

$$2(+1) + x + 4(-1) + (-2) = 0$$

Solving for x, we get:

$$2 + x - 4 - 2 = 0$$

$$x = +4$$

Hence, the oxidation state of chromium in $Na_2[CrF_4O]$ is IV.

The correct IUPAC name of $Fe_4[Fe(CN)_6]_3$ is ?

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Explanation

The correct IUPAC name of $Fe_4[Fe(CN)_6]_3$ can be determined by breaking down the complex. In this complex, $Fe$ is in two different oxidation states. The $[Fe(CN)_6]^{3-}$ ion is called hexacyanoferrate(III), indicating that the iron in this part of the complex is in the +3 oxidation state. The four $Fe$ atoms outside the brackets balance the charge of the hexacyanoferrate ions. Therefore, the IUPAC name for this complex is Iron(III) hexacyanoferrate(II).

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