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Zeigler-Natta catalyst is used for which type of reaction.

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Explanation

The Ziegler-Natta catalyst is used in the polymerization of alkenes to produce polymers like polyethylene and polypropylene. This catalyst allows for the control of the polymer structure and molecular weight.

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An aqueous solution of potash Alum gives.

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Carnalite in solution in H2O shows the properties of.

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Explanation

Carnallite is a mineral composed of hydrated potassium magnesium chloride, with the formula KMgCl3·6H2O. When dissolved in water, it dissociates into its constituent ions: $K^+$, $Mg^{2+}$, and $Cl^-$. So, the correct option is $K^+, Mg^{2+}, Cl^-$. Hence, option o1 is correct.

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Number of ions present in aqueous solution of $Fe_4 [Fe(CN)_6]_3 $ is

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Explanation

The compound $Fe_4[Fe(CN)_6]_3$ dissociates in water to produce 4 $Fe^{3+}$ ions and 3 $[Fe(CN)_6]^{4-}$ ions. The total number of ions in solution is 4 + 3 = 7. Therefore, the correct option is 7 ions. Hence, option o3 is correct.

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How many ions are produced in aqueous solution of $[CoH_2O)_6] Cl_2$ ?

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Explanation

The compound $[Co(H_2O)_6]Cl_2$ dissociates in water to form one $[Co(H_2O)_6]^{2+}$ ion and two $Cl^-$ ions. Thus, the total number of ions produced is 1 + 2 = 3. Therefore, the correct option is 3 ions. Hence, option o2 is correct.

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The formula of dichlorido bis (urea) copper (II) is ?

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Explanation

The correct formula for dichlorido bis (urea) copper (II) is $ [CuCl_2(O=C(NH_2)_2)_2] $. In this complex, the copper ion (Cu^2+) is coordinated to two chloride ions (Cl^-) and two urea molecules. This is indicated by the bis (urea) and dichlorido in the name.

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Correct formula of diammine silver (I) chloride is ?

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Explanation

The correct formula for diammine silver (I) chloride is $ [Ag(NH_3)_2]Cl $. In this complex, the silver ion (Ag^+) is coordinated to two ammonia molecules (NH_3), forming the diammine complex, and there is one chloride ion (Cl^-) balancing the charge.

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The formula of sodium nitroprusside ?

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Explanation

The correct formula for sodium nitroprusside is $ Na_2[Fe(CN)_5NO] $. In this complex, the iron (Fe) is in the +3 oxidation state and is coordinated to five cyanide ions (CN^-) and one nitrosyl group (NO). There are two sodium ions (Na^+) to balance the charge of the complex.

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The oxidation numbers of chromium in $Na_2[CrF_4O] $ complex is ?

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Explanation

To determine the oxidation state of chromium in $Na_2[CrF_4O]$, we need to consider the charges of the other components in the complex. Sodium (Na) has an oxidation state of +1. Fluoride (F) has an oxidation state of -1, and oxygen (O) usually has an oxidation state of -2. Let the oxidation state of chromium be x. The net charge of the complex ion $[CrF_4O]^{2-}$ should be equal to -2. Therefore, the equation can be set up as follows:

$$2(+1) + x + 4(-1) + (-2) = 0$$

Solving for x, we get:

$$2 + x - 4 - 2 = 0$$

$$x = +4$$

Hence, the oxidation state of chromium in $Na_2[CrF_4O]$ is IV.

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The correct IUPAC name of $Fe_4[Fe(CN)_6]_3$ is ?

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Explanation

The correct IUPAC name of $Fe_4[Fe(CN)_6]_3$ can be determined by breaking down the complex. In this complex, $Fe$ is in two different oxidation states. The $[Fe(CN)_6]^{3-}$ ion is called hexacyanoferrate(III), indicating that the iron in this part of the complex is in the +3 oxidation state. The four $Fe$ atoms outside the brackets balance the charge of the hexacyanoferrate ions. Therefore, the IUPAC name for this complex is Iron(III) hexacyanoferrate(II).

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