In which of the following compound of trantion metal ion has 4.90 BM magnetic momentum?
The magnetic moment can be calculated using the same formula: $$ ext{Magnetic Moment} ( ext{BM}) = ext{n(n+2)} $$, where 'n' is the number of unpaired electrons. For $Fe^{2+}$ in $FeSO_4$, which has an electron configuration of [Ar] 3d^6, there are 4 unpaired electrons. Therefore, the magnetic moment is approximately 4.90 BM.