NEET Practice Questions (MCQs) with Answers & Solutions

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Addition of Hydrobromic acid with Ethyne gives finally

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Explanation

$ CH \equiv CH \xrightarrow [] {HBr} CH_2 = CH - Br \xrightarrow [] { Hbr} CH_3-CHBr_2 $ Ethylidene bromide

Addition of HCN to Acetylene in presence of $ Ba (CN)_2 $ gives

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Explanation

$ CH \equiv CH \xrightarrow [] { HCN} CH_2 = CH - CN $

What is the product formed when acetylene reacts with hypochlorous acid ?

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But-1-yne on Oxidation with hot alkeline $ KMnO_4 $ gives

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Explanation

$ CH_3 -CH_2 - C \equiv CH \xrightarrow[] { KMnO4 / KOH } CH_3 CH_2 COOH + CO_2 + H_2 O $ (terminal alkyne) Oxidation of terminal alkyne gives acid and $ CO_2 $

But-2-yne on Oxidation with hot alkeline $ KMnO_4 $ gives.

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Explanation

$ CH_3 -C \equiv C - CH_3 \xrightarrow [KOH] { KMnO_4} CH_3COOH + CH_3COOH $ (nonterminal alkyne) Oxidation of nonterminal alkyne gives mixture of two acids

Acetylene reacts with Ethyl magnesium bromide to give

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Explanation

$ CH \equiv CH + CH_3CH_2 MgBr \rightarrow CH_3CH_3 + CH \equiv CMgBr $

The Compound $X (C_5H_8 ) $ greacts with Ammonical $ AgNO_3 $ to gives a white ppt and on oxidation with hot alk, $KMnO_4 $ gives acid $( CH_3)_2 CHCOOH $ therefore X is

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Explanation

According to Que-76

Reductive Ozonolysis of But-2-yne gives

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Explanation

Reductive ozonolysis of But-2-yne gives Buta-2,3-dione. In reductive ozonolysis, the alkyne is cleaved by ozone (O3) and reduced to form diketones. Specifically, But-2-yne is broken down into two molecules of Buta-2,3-dione as the carbon-carbon triple bond is split and each carbon forms a double bond with oxygen.

2- hexyne gives trans-2-hexene on treatment with

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Explanation

The reduction of alkynes to trans-alkenes can be achieved using sodium or lithium in liquid ammonia. This is known as the Birch reduction. For 2-hexyne, using $ Li / NH_3 $ will yield trans-2-hexene.

Which carbide react with water to give propyne ?

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Explanation

$ Mg_2C_3 + 4 H_2O \rightarrow CH_3 - C \equiv CH + 2 Mg (OH)_2 $

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