Addition of Hydrobromic acid with Ethyne gives finally
$ CH \equiv CH \xrightarrow [] {HBr} CH_2 = CH - Br \xrightarrow [] { Hbr} CH_3-CHBr_2 $ Ethylidene bromide
Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Addition of Hydrobromic acid with Ethyne gives finally
$ CH \equiv CH \xrightarrow [] {HBr} CH_2 = CH - Br \xrightarrow [] { Hbr} CH_3-CHBr_2 $ Ethylidene bromide
Addition of HCN to Acetylene in presence of $ Ba (CN)_2 $ gives
$ CH \equiv CH \xrightarrow [] { HCN} CH_2 = CH - CN $
What is the product formed when acetylene reacts with hypochlorous acid ?
But-1-yne on Oxidation with hot alkeline $ KMnO_4 $ gives
$ CH_3 -CH_2 - C \equiv CH \xrightarrow[] { KMnO4 / KOH } CH_3 CH_2 COOH + CO_2 + H_2 O $ (terminal alkyne) Oxidation of terminal alkyne gives acid and $ CO_2 $
But-2-yne on Oxidation with hot alkeline $ KMnO_4 $ gives.
$ CH_3 -C \equiv C - CH_3 \xrightarrow [KOH] { KMnO_4} CH_3COOH + CH_3COOH $ (nonterminal alkyne) Oxidation of nonterminal alkyne gives mixture of two acids
Acetylene reacts with Ethyl magnesium bromide to give
$ CH \equiv CH + CH_3CH_2 MgBr \rightarrow CH_3CH_3 + CH \equiv CMgBr $
The Compound $X (C_5H_8 ) $ greacts with Ammonical $ AgNO_3 $ to gives a white ppt and on oxidation with hot alk, $KMnO_4 $ gives acid $( CH_3)_2 CHCOOH $ therefore X is
According to Que-76
Reductive Ozonolysis of But-2-yne gives
Reductive ozonolysis of But-2-yne gives Buta-2,3-dione. In reductive ozonolysis, the alkyne is cleaved by ozone (O3) and reduced to form diketones. Specifically, But-2-yne is broken down into two molecules of Buta-2,3-dione as the carbon-carbon triple bond is split and each carbon forms a double bond with oxygen.
2- hexyne gives trans-2-hexene on treatment with
The reduction of alkynes to trans-alkenes can be achieved using sodium or lithium in liquid ammonia. This is known as the Birch reduction. For 2-hexyne, using $ Li / NH_3 $ will yield trans-2-hexene.
Which carbide react with water to give propyne ?
$ Mg_2C_3 + 4 H_2O \rightarrow CH_3 - C \equiv CH + 2 Mg (OH)_2 $
Ready to ace NEET?
Free access · No credit card required
Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.
No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.
The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.