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NEET Practice Questions (MCQs) with Answers & Solutions

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Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: " The boiling points of alkylisocyanides are lower than their isomeric alkyl cyanides." Statement - 2: "Isocyanide group is polar, so its boiling points is higher than their isomeric alkyl cyanides."

A. Statement - 1 is True; Statement - 2 is True ; Statement - 2 is a correct explanation for Statement - 9 B. Statement - 1 is True; Statement - 2 is True; Statement - 2 is Not a correct explanation for Statement - 9 C. Statement - 1 is True; Statement - 2 is False D. Statement - 1 is False; Statement - 2 is True.

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An organic compound (A) on reduction gives compound (B) on treatment with $CHCl_3$ and alcoholic KOH gives (C) on Catalytic reduction gives N - Methyl aniline. The compound (A) is........

A. Methylamine B. Aniline C. Nitrobenzene D. Nitro methane

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Explanation

The compound (A) is Nitrobenzene which upon reduction gives Aniline (B). When treated with $CHCl_3$ and alcoholic KOH, it forms Phenyl isocyanide (C). On catalytic reduction, Phenyl isocyanide forms N-Methyl aniline. Hence, the correct answer is Nitrobenzene.

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Which is formed when $(CH_3)_4 â€“ N â€“ OH$ is heated ?

A. $ CH_3 NH_2 $ B. $ C_2 H_5 NH_2 $ C. $ (CH_3)_3 N $ D. $ (CH_3)2 NH $

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Explanation

$ (CH_3)_4.N. OH \xrightarrow [{}] { { \triangle } } [ (CH_3)_3N ]+ CH_3 OH $

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Which of the following reactant produced Benzanilide when it treated with aniline ?

A. Acetic anhydride B. Benzenamide C. Acetyl chloride D. Benzoyl chloride

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Explanation

Benzanilide is formed when aniline reacts with benzoyl chloride. The reaction is an example of Schotten-Baumann reaction, where an amine reacts with an acyl chloride to form an amide. The equation for the reaction is:

$$ ext{C}_6 ext{H}_5 ext{NH}_2 + ext{C}_6 ext{H}_5 ext{COCl} ightarrow ext{C}_6 ext{H}_5 ext{NHCOC}_6 ext{H}_5 + ext{HCl} $$

Here, benzoyl chloride (C$_6$H$_5$COCl) is the reactant that produces benzanilide when treated with aniline.

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Which of the following is the strongest base in aqueous solution ?

A. Methylamine B. Aniline C. Trimethylamine D. Dimethylamine

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Explanation

Dimethylamine is the strongest base in aqueous solution among the given options. This is because dimethylamine has two electron-donating methyl groups, which increase the electron density on the nitrogen atom, making it more willing to donate its lone pair of electrons. The order of basicity for amines generally follows:

$$ ext{Dimethylamine} > ext{Methylamine} > ext{Trimethylamine} > ext{Aniline} $$

Hence, dimethylamine (CH$_3$)$_2$NH is the strongest base.

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How many primary amines are possibile with the formula of $C_4 H_{11} N $ ?

A. 1 B. 2 C. 3 D. 4

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Explanation

Four (n - butylamine, isobutylamine, sec-butylamine, ter-butylamine)

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Which of the following is not the correct reaction of aryldiazonium salts ?

A. $C_ 6H_5 N_2^+ Cl^- + CuCl \rightarrow C_6H_5Cl $ B. $ C_6 H_5 N_2^Cl^- + HBF_4 \rightarrow C_6 H_5 F $ C. $ C_6H_5 N^+_2 Cl ^ - + H_3 PO_2 \rightarrow C_6H_5PO_4 $ D. $ C_6 H_5 N_2 ^+ Cl ^- + SnCl_2 / HCl \rightarrow C_6 H_5 NHNH_2 $

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Explanation

The reaction given in option o3 is not correct. Aryldiazonium salts react with hypophosphorous acid (H$_3$PO$_2$) to give the corresponding aryl compound (benzene in this case), not an aryl phosphate. The correct reaction is:

$$ ext{C}_6 ext{H}_5 ext{N}_2^+ ext{Cl}^- + ext{H}_3 ext{PO}_2 ightarrow ext{C}_6 ext{H}_6 + ext{N}_2 + ext{HCl} $$

Therefore, option o3 is the incorrect reaction.

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No. of o and $ \nu $ bonds contains Allyl isocyanide are _ _and _ _

A. $ 9 \sigma and 3 \pi $ B. $ 9 \sigma and 9 \pi $ C. $ 3 \sigma and 4 \pi $ D. $ 5 \sigma and 7 \pi $

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Explanation

$ CH_2 = CH - CH_2 - N^+ \equiv C^ - $ (allyl isocyanide)

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Gas evolved during the reaction of Na-metal on $ C_2H_5NH_2 $ is :

A. $ N_2 $ B. $ H_2 $ C. $ C_2H_2 $ D. $ CO_2 $

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Explanation

$ 2C_2H_5NH_2 + 2Na \rightarrow 2C_2H_5 NHNa + H_2 $

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The action of nitrous acid on an aliphatic primary amine, gives :

A. alcohol B. alkylnitrite C. secondary amine D. nitro alkane

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Explanation

$ R- NH_2 +HNO_2 \rightarrow R - OH + N_2 + H_2O $ Aliphatic amine Alcohol

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