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NEET NEET Questions — Free MCQ Practice

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Which of the following reagent is used to convert Butan-2-one into propnroic acid

A. $ NaOH I_2 /H^+ $ B. Fehling Solution C. Tollen's reagent D. $ NaOH, NaI/H^+$

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Explanation

The reagent $ NaOH I_2 /H^+ $ is used for the iodoform test, which specifically converts methyl ketones (or secondary alcohols adjacent to a methyl group) into carboxylic acids with one carbon less. In the case of butan-2-one, it will be converted into propanoic acid using this reagent.

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By which of the following proceducres can ethyl n-propyl ether be obtained ?

A. $ C_2 H_5 OH \xrightarrow [] { { HBr}} I \xrightarrow [ { ether } ] { { Mg} } II \xrightarrow [] { { H_2 O} } III \xrightarrow [ { C_2 H_5 Br } ] { { Na } } $ B. $ C_2 H_5 OH \xrightarrow [] { { HBr}} I \xrightarrow [ { ether } ] { { Mg}} II \xrightarrow [{ 2.H_3O^+} ] { {1.CH_2 O } } III \xrightarrow [ { C_2 H_5 Br } ] { { Na } } $ C. $ C_2 H_5 OH + H_2 SO_4 \xrightarrow [] { { 140 ^\circ C } } $ D. $ C_2 H_5 OH + Conc . H_2 SO_4 \xrightarrow [] { { 180 ^\circ C } } I \xrightarrow [{ CH_3 CH_2 CH_2 Br} ] { { } } $

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Cross aldol condensation occurs betwee n

A.

two same aldehydes

B.

two same ketones

C.

two different aldehydes and ketones

D.

two same acids

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Explanation

Cross aldol condensation occurs between two different aldehydes and ketones. This type of reaction involves the formation of a carbon-carbon bond between the alpha carbon of one carbonyl compound and the carbonyl carbon of another, resulting in a Î²-hydroxy ketone or Î²-hydroxy aldehyde.

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Pentane - 3 - one is not obtained from

A.

2,2- dichloro pentane

B.

3,3- dichloro pentane

C.

pentan -3- ol

D.

pent -2- yne

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$ C_2H_5CHO and (CH_3 ) CO $ be distiguished by testing with

A. phenyl hydrazine B. hydroxyl amine C. Fehilng Solution D. sodium bisulphide

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Explanation

Fehling's solution is used to distinguish between aldehydes and ketones. $C_2H_5CHO$ (an aldehyde) will reduce Fehling's solution, forming a red precipitate of copper(I) oxide, while $(CH_3)_2CO$ (a ketone) will not react with Fehling's solution.

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Which of the following has the most acidic hydrogen ?

A. hexan-3-one B. hexan 2,4- dione C. hexan 2,5-dione D. hexan 2,3-dione

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Explanation

Hexane-2,4-dione has the most acidic hydrogen due to the presence of two carbonyl groups (C=O) that increase the acidity of the hydrogen atoms on the methylene group (CH_2) between them. The inductive and resonance effects of the carbonyl groups make the hydrogen atoms more acidic.

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$ CH_3 - CHO + HCN \rightarrow A, $ compound A on hydrolysis gives

A. $ CH_3 - CH_2 - COOH $ B. $ CH_3 - CH_2 - CH_2 - NH_2 $ C. $ CH_3CH_2 - CH_2COOH $ D. $ CH_3CH (OH) - COOH $

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Explanation

$CH_3CHO$ (acetaldehyde) reacts with HCN to form $CH_3CH(OH)CN$, which upon hydrolysis gives $CH_3CH(OH)COOH$ (lactic acid). The reaction involves the addition of HCN followed by hydrolysis.

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What will be the final product "Z" of the following reaction ? $ CH_3 CH_2COOH \xrightarrow [{(ii) \triangle } ] { { (i) NH_3 }} X \xrightarrow [ { (ii) HNO_3} ] { { (i) Br_2 / KOH } } Y \xrightarrow [] { { KMnO_4 / H_2 SO_4 } } Z $

A. propan-1-ol B. propan-1-amine C. ethanoic acid D. propanal

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A compound, containing only carbon, hydrogen and oxygen, has a molecular weight of 44. On complete oxidation it is converted in to a compound of molecular weight 60. The original compound is

A. an aldehyde B. an acid C. an alcohol D. an ether

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Explanation

To solve this, we need to determine the original compound based on the molecular weights given.

Molecular weight of the original compound: 44.
Molecular weight after complete oxidation: 60.

The molecular formula corresponding to a molecular weight of 44 is likely $C_2H_4O$. Complete oxidation of $C_2H_4O$ yields $CO_2$ and $H_2O$.

The original compound is an aldehyde (ethanal) because on oxidation, an aldehyde converts into an acid (ethanoic acid) with a molecular weight of 60. Therefore, the correct answer is 'an aldehyde'.

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Which one does not give Can izaro's reaction ?

A. benzaldehyde B. 2- methyl propanal C. p - methoxy benzaldehy de D. 2,2- dimethyl propanal

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