NEET Practice Questions (MCQs) with Answers & Solutions

Catenation is the ability of an element to form bonds with itself. Carbon (C) has the highest tendency to undergo catenation due to its small size and strong C-C bonds. As we move down the group in the periodic table, the tendency to undergo catenation decreases. Therefore, among the given options, tin (Sn) has the least tendency to undergo catenation.

$ SiO_2 + 3C \rightarrow SiC + 2CO $

It reacts with alkali as well as acid.

$ R_3SiCl on hydrolysis form only a dimer R_3 SiOH + HOSiR_3 \rightarrow R Si_3 - O - SiR_3 $ .

$ CCl_4 + H_2O \rightarrow$ No reaction d - orbital absent in carbon atom

excess of one valence electron in P atom over Si will form n type conductor.

$ C + 2H_2SO_4 \rightarrow CO_2 + 2H_2O + 2SO_2 $ Here carbon is oxidized to $ CO_2 \& H_2SO_4 is reduced to SO_2 $

Silica on heating with carbon at elevated temp gives carborandum (Silicon Carbide) $ SiO_2 + 3C \rightarrow [] { { \triangle } } SiC + 2CO_2 $ Carborandum is very hard substance

Organic acids dissolve lead in presence of oxygen $ Pb + 2CH_3COOH + {1/2} O_2 \rightarrow Pb (CH_3COO)2 + H_2O $

Lead (Pb) commonly exhibits +2 and +4 oxidation states. The +2 oxidation state is more stable for lead due to the inert pair effect, where the 6s electrons are less available for bonding. Thus, the correct oxidation states of lead are +2 and +4.