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$ SO_2 + H_2S \rightarrow X $. The final product is
When sulfur dioxide (\(SO_2\\)) reacts with hydrogen sulfide (\(H_2S\\)), the reaction produces water (\(H_2O\\)) and sulfur (\(S\\)). This can be represented by the chemical equation: $$SO_2 + 2H_2S \\rightarrow 2H_2O + 3S$$.
Sulphur in +3 oxidation state is present in
Dithionous acid, also known as hydrosulfurous acid, has the chemical formula \((H_2S_2O_4)\\). In this compound, sulfur is present in the +3 oxidation state. This can be determined by calculating the oxidation states of sulfur in the compound.
$ H_2S $ is not a/an
Hydrogen sulfide (\( H_2S \)) is primarily known as a reducing agent because it can donate electrons in a chemical reaction. It is also acidic in nature. However, it is not known as an oxidizing agent since it cannot accept electrons in a reaction. Therefore, \( H_2S \) is not an oxidizing agent.
Which one of the following is non-reducing
Among the given options, \( H_2O \) (water) is non-reducing. The other molecules like \( H_2S \), \( H_2Te \), and \( H_2Se \) have reducing properties due to the presence of hydrogen that can be donated in a reaction. Water does not act as a reducing agent under normal conditions.
$ When PbO_2 reacts with conc. HNO_3 $ the gas evolved is
The most efficient agent for the absorption of $ SO_3 $ is
The most efficient agent for the absorption of $SO_3$ is $98 ext{ extpercent} ext{H}_2 ext{SO}_4$. This is because $98 ext{ extpercent} ext{H}_2 ext{SO}_4$ has a high concentration of sulfuric acid, which allows it to effectively absorb sulfur trioxide ($SO_3$) and form oleum. Lower concentrations of sulfuric acid do not absorb $SO_3$ as efficiently.
The correct order of thermal stability of hydrogen halide.
$ HF \gt HCl \gt HBr \gt HI $ thermal stability
Phosgene is common name of
$ CHCl_3 + ½ O_2 \rightarrrow COCl_2 + HCl $ Phosgene or carbonyl chloride
The solubility of iodine in water increases in presence of
Iodine has the least affinity for water and is only slightly soluble in it . However it is dissolved in 10% aq. Solution of KI due to formation of complex ion ie . $ I_3 $ $ I_2 + KI \rightleftharpoons KI_3 or I_2 + I^- \rightleftharpoons I^-_3 $ (Complex)
Bromine is obtained on commercial scale from
Carnellite is $ KCl. Mg Cl_2.6H_2 O $ . The mother liquor remain after crystallisation of KCl from carnellite contains about 0.25% of Bromine as $ MgBr_2 or KBr$ .
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