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In group - I , 2 and 3 electrolytc and products at anode and cathode arc mentioned respectively match them appropriately.

Group -1

(1) NaCl (molten)

(2) NaCl (conc. aqueous) (

3) NaCl (dilute aqeous)

(4) $ Al_20_3 , ( +Na_3AIF_6) $

(5) $ KIIF_2 anhydrous HF $

Group -2

(A) $ O_{2(g)} $

(B) $ O_{2(g)} , CO_{(2(g)} $

(C) $ Cl_{2(g)} $

(D) $ F_{2(g)} $

(E) $ H_{2(g)} $

Group-3

(P) Al metal

(Q) $ Cl_{2(g)} $

(R) Na metal

(S) $ H_{2(g)} and in solution NaOH$

(T ) $ H_{2(g)} $

A.

(1) -(.C) - (.R),

(2) - (.C) - (T) ,

(3)- (A) - (T),

(4) - ( B) - (P) ,

(5) - (D) - ( T)

B.

(1) -(.C) - (.R), (2) - (.C) - (S) , (3)- (A) - (T),. (4) - ( B) - (P) ,. (5) - (D) - ( T)

C.

(1) -(.C) - (.R), (2) - (.C) - (S) , (3)- (A) - (Q), (4) - ( B) - (P) , (5) - (D) - ( T)

D.

(1) -(.C) - (.R), (2) - (.C) - (S) , (3)- (C) - (T), (4) - ( B) - (P) , (5) - (D) - ( T)

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Explanation

The correct match is: (1) - (C) - (R), (2) - (C) - (S), (3) - (A) - (T), (4) - (B) - (P), (5) - (D) - (T). This matches the electrolytes (molten/aqueous NaCl, Al2O3, KHF2) with the respective products formed at the anode and cathode during electrolysis.

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Potential of a Std. half cell is measured by potentiometer connecting it with S .11.E. here S.H.E. act as anode then potential of half cell would be equals to

A. $ E ^ 0 _{ox} $ of the other electrode B. $ E ^ o_{red } $ of the other electrode C. $ E_{ox} $ of the other electrode D. $ E_{red} $ of the other electrode

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will be the decrease in the concentration Of $ Ni ^ {2+}_{(aq)} When the reaction Co_(s) + Ni ^ {2+} _{(aq, 0.1 M )} \rightleftharpoons Co^{2+} _{(aq, 0.01 M )} + Ni _{(S)} $ reaches the equilibrium ?

A. 9.78% B. 8.74% C. 95.40% D. 92.50%

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The alkali metals are low melting. Which of the following alkali metal is expected to melt if the room tempreature rises to $30^\circ C$ ?

A. Na B. K C. Rb D. Cs

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Explanation

Melting point decreases as the strength of metallic bonding decreases with increasing size of the atom.

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The reducing power of a metal depends on various factors. Suggest the factor which makes Li, the strongest reducing agent in aqueous solution.

A. Sublimation enthalpy B. Ionisation enthalpy C. Hydration enthalpy D. Electron - gain enthalpy

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Explanation

Due to small size of the $ Li^+$ , its hydration enthalpy is the highest and hence Li is the strongest reducing agent.

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Metal carbonates decompose on heating to give metal oxide and carbondioxide. Which of the metal carbonates is most stable thermally ?

A. $ MgCO_3 $ B. $ CaCO_3 $ C. $ SrCO_3 $ D. $ BaCO_3 $

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Explanation

Thermal stability of metal carbonates increases as the electropositive character of the metal or the basicity of the metal hydroxide increases from $ Be(OH)_2 to Ba(OH)_2, Thus, BaCO_3 $ is the most stable.

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Which of the following metal hydroxide is the least basic ?

A. $ Mg (OH)_2 $ B. $ Ca(OH)_2 $ C. $ Sr(OH)_2 $ D. $ Ba(OH)_2 $

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Explanation

As the ionisation enthalpy increases from $ Mg \rightarrow Ba $ the M - O bond becomes weaker and weaker down the group, and hence basicity increases down the group. Thus, $ Mg(OH)_2 $ is least basic.

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Some of the group - 2 metal halides are covalent and soluble in organic solvents. Among the following metal halides, the one which is soluble in ethanol is ....

A. $ BeCl_2 $ B. $ MgCl_2 $ C. $ CaCl_2 $ D. $ SrCl_2 $

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The solubility of metal halides depends on their nature, lattice enthalpy and hydration enthalpy of the individual ions. Among the fluorides of alkali metals, the lowest solubility of LiF in water is due to...

A. Ionic nature of lithium fluoride B. High lattice enthalpy C. High hydration enthalpy for lithium ion. D. Low ionisation enthalpy of lithium atom

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Explanation

Due to small size of Li+ and Fâ€“ ions, lattice enthalpy is much higher than hydration enthaalpy and hence LiF is least soluble among alkali metal Fluorides.

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Amphoteric hydroxides react with both alkalies and acids. Which of the following Group - 2 metal hydroxides is soluble in sodium hydroxide ?

A. $ Be(OH)_2 $ B. $ Mg(OH)_2 $ C. $ Ca(OH)_2 $ D. $ Ba(OH)_2 $

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Explanation

$ Be(OH)_2 $ being amphoteric dissolves in NaOH.

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