In the standardization of $ Na_2S_2O_3 using K_2Cr_2O_7 by iodometry, the equivalent weight of K_2Cr_2O_7 $ is (IIT JEE 2001)
$ During the reaction, Cr_2O_7 ^{ 2-} changes to Cr^{3+} $. Hence the change in oxidation number of Cr is 6. $ \therefore Equivalent weight = { Molar mass \over 6 } $