Are these NEET questions free to attempt?

Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

Do I need an account to practise NEET MCQs?

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

Are these previous year NEET questions?

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.

NEET NEET Questions — Free MCQ Practice

● ● ● ● ●

A particle of mass 1 kg is kept at (1m, 1m, 1m). The moment of inertia of this particle about z-axis would be

A.

$1 kg - m^{2}$

B.

$2 kg - m^{2}$

C.

$3 kg - m^{2}$

D.

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$|\vec{r}| = \sqrt{(1^{2} + 1^{2})} = \sqrt{2} m I = {mr}^{2} = 1 \times {(\sqrt{2})}^{2} = 2 kg - m^{2}$

● ● ● ● ●

A wheel is rotating at the rate of 33 rev/min. If it comes to stop in 20 s. Then, the angular retardation will be

A.

$π \frac{rad}{s^{2}}$

B.

$11 π rad / s^{2}$

C.

$\frac{π}{200} r a d / s^{2}$

D.

$\frac{11 π}{200} r a d / s^{2}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$α = \frac{ω_{0}}{t} (0 = ω_{0} - α t) = \frac{2 π \times 33 / 60}{20} = \frac{11 π}{200} r a d / s^{2}$

● ● ● ● ●

A solid sphere is rotating about a diameter at an angular velocity $ω$ . If it cools so that its radius reduces to $\frac{1}{n}$ of its original value, its angular velocity becomes [MP PMT 2006]

A.

$\frac{ω}{n}$

B.

$\frac{ω}{n^{2}}$

C.

$n ω$

D.

$n^{2} ω$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

On applying law of conservation of angular momentum

$I_{1} ω_{1} = I_{2} ω_{2}$

For solid sphere,

$I = \frac{2}{5} m r^{2} \Rightarrow \frac{2}{5} m r_{1}^{2} ω_{1} = \frac{2}{5} m r_{2}^{2} ω_{2} r^{2} ω = {(\frac{r}{n})}^{2} ω_{2} \Rightarrow ω_{2} = n^{2} ω$

● ● ● ● ●

A horizontal platform is rotating with uniform angular velocity around the vertical axis passing through its centre. At some instant of time a viscous fluid of mass 'm' is dropped at the centre and is allowed to spread out and finally fall. The angular velocity during this period

A.

Decreases continuously

B.

Decreases initially and increases again

C.

Remains unaltered

D.

Increases continuously

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

According to law of conservation of momentum,

I $ω$ = constant.

When viscous fluid of mass m is dropped and start spreading out then its moment of inertia increases and angular velocity decreases. But when it falls from the platform moment of inertia decreases so angular velocity increases again.

● ● ● ● ●

For the same total mass, which of the following will have the largest moment of inertia about an axis passing through the centre of gravity and perpendicular to the plane of the body?

A.

A disc of radius a

B.

a ring of radius a

C.

a square lamina of side 2 a

D.

four rods forming square of side 2 a.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$l_{disc} = M \frac{a^{2}}{2}; l_{ring} = {Ma}^{2} l_{square lamina} = M (\frac{L^{2} + B^{2}}{12}) = M \frac{4 (a^{2} + a^{2})}{12} = \frac{2 {Ma}^{2}}{3} l_{rods} = [\frac{M}{4} x \frac{4 a^{2}}{12} + \frac{M}{4} x {(\frac{2 a}{2})}^{2}] x 4 = \frac{4 {Ma}^{2}}{3}$

● ● ● ● ●

The radius of gyration of a uniform rod of length L about an axis passing through its centre of mass is

A.

$\frac{L}{2 \sqrt{3}}$

B.

$\frac{L^{2}}{12}$

C.

$\frac{L}{\sqrt{3}}$

D.

$\frac{L}{\sqrt{2}}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$K = \sqrt{\frac{I}{M}} = \sqrt{\frac{(m L^{2} / 12)}{m}} = \frac{L}{2 \sqrt{3}}$

● ● ● ● ●

Two uniform, thin identical rods each of mass M and length l are joined together to form a cross. What will be the moment of inertial of the cross about an axis passing through the point at which the two rods are joined and perpendicular to the plane of the cross

A.

$\frac{M l^{2}}{12}$

B.

$\frac{M l^{2}}{6}$

C.

$\frac{M l^{2}}{4}$

D.

$\frac{M l^{2}}{3}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$I = 4 [\frac{M}{2} \frac{{(l / 2)}^{2}}{3}] = \frac{M I^{2}}{6}$

● ● ● ● ●

If the linear momentum is increased by 50%, the kinetic energy will increase by

A.

50%

B.

100%

C.

125%

D.

25%

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$\begin{array}{l} Let p_{1} = p, p_{2} = p_{1} + 50 % of p_{1} = p_{1} + \frac{p_{1}}{2} = \frac{3 p_{1}}{2} \\ \begin{aligned} E & \propto p^{2} \end{aligned} \end{array} \Rightarrow \begin{aligned} \frac{E_{2}}{E_{1}} & = {(\frac{p_{2}}{p_{1}})}^{2} \end{aligned} = {(\frac{3 p_{1} / 2}{p_{1}})}^{2} = \frac{9}{4} \Rightarrow \begin{aligned} E_{2} & = 2 .25 E_{2} = E_{1} + 1 .25 E_{1} \end{aligned} ∴ \begin{aligned} E_{2} & = E_{1} + 125 % of E_{1} \end{aligned}$

i.e., Kinetic energy will increase by 125%.

● ● ● ● ●

A solid sphere, a hollow sphere, and a disc, all having the same mass and radius, are placed at the top of a smooth incline and released. Least time will be taken in reaching the bottom by

A.

the solid sphere

B.

the hollow sphere

C.

the disc

D.

all will take the same time

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Acceleration of all bodies on smooth surface = g sin $θ$ (equal)

$∴$ All bodies will take equal time.

● ● ● ● ●

A bullet of mass m and velocity v is fired into a block of mass M and sticks to it. The final velocity of the system equals

A.

$\frac{M}{m + M} . v$

B.

$\frac{m}{m + M} . v$

C.

$\frac{m + M}{m} . v$

D.

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$mv = (m + M) v' ∴ v' (\frac{m}{m + M}) v$

NEET Practice Questions (MCQs) with Answers & Solutions

Frequently Asked Questions