NEET Practice Questions (MCQs) with Answers & Solutions

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Two perfectly elastic particles A and B of equal mass traveling along the line joining them with velocities 15 m/s and 10 m/s. After the collision, their velocities will be 

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A small disc of radius 2 cm is cut from a disc of radius 6 cm. If the distance between their centres is 3.2 cm, what is the shift in the centre of mass of the disc?

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From a circular disc of radius R, a square is cut out with a radius as its diagonal.  The centre of mass of remainder is at a distance (from the centre)

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Two bodies with moment of inertia I1 and I2 (I1>I2) and have equal angular momenta.  If KE of rotation are E1 and E2, then

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Explanation

E1=12I1ω12,  E2=12I2ω22As I1ω1=I2ω2I12ω12=I22ω22 ; I1I1ω12=I2I2ω22I1ω12I2ω22=I2I1 or 12I1ω1212I2ω22=E1E2=I2I1<1E1<E2

A mass m with velocity u strikes a wall normally and returns at the same speed. What is the magnitude of the change in momentum of the body when it returns

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Two particles of equal mass have coordinates (2m,4m,6m) and (6m,2m,8m). Of these one particle has velocity v1=2i^ m/s and another particle has velocity v2=2j^ m/s at time t = 0. The coordinate of their centre of mass at time t = 1 s will be

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Explanation

After 1 s, coordinates of first particle will become (4m,4m,6m) and co-ordinates of second particle will become (6m,4m,8m)

 Xcm=4+62=5m    Ycm=4+42=4m    Zcm=6+82=7m

Note : In this problem answer is independent of the fact whether the first particle has velocity v1 or v2. Think why?

The M.I. of a body about the given axis is 1.2 kg x m2 initially the body at rest. In order to the rotational kinetic energy of 1500 J, the angular acceleration of 25 rad/sec2 must be about that axis for the duration of

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Explanation

2.

Rotational kinetic energy=122=1500                 12×1.2×ω2=1500ω2=30001.2ω=50rad/sInitially the body was at rest and after t sec its angular velocity becomes 50 rad/sω = ω0 + αt  50 = 0 + 25 × t  t = 2s

A loop rolls down on the inclined plane. The fraction of its total kinetic energy that is associated with rotational motion is

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Explanation

1.

Fraction=(KE)rot(KE)rot+(KE)trans=12212l02+12mv2

A ball kept in a closed box moves in the box making collisions with the walls. The box is kept on a smooth surface. The velocity of the centre of mass

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Explanation

No external force is zero. Hence velocity of CM of the box and ball system will remain constant

 A body of mass m1 moving with a velocity 3 ms-1 collides elastically with another body  at rest of mass m2. After collision the velocities of the two bodies are 2 ms-1 and 5 ms-1 respectively along the direction of motion of m2. The ratio m1m2 is

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