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 The area of cross-section of a wire of length 1.1 metre is 1mm2.It is loaded with 1 kg. If Young's modulus of copper is 1.1×1011N/m2, then the increase in length will be (If g=10m/s2)

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Explanation

(c) l=mgLAY=1×10×1.11.1×1011×10-6m=0.1mm

In CGS system, the Young's modulus of a steel wire is 2×1012 dyne/cm2 . To double the length of a wire of unit cross-section area, the force required is 

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Explanation

(b) To double the length of wire,

Stress = Young's modulus

                                   FA=2×1012dynecm2

If A=1 then F=2 × 1012dyne

The material which practically does not show elastic after effect is 

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Explanation

(d) When a elastic body is stretched and applied deforming force is removed then the body is expected to return to its original configuration instantaneously. But sometimes some materials take some time to return to its original configuration. This temporary delay in achieving its original configuration is termed as elastic after effect. This elastic after effect is very short for quartz fiber. But elastic after effect is more for glass. 

A force F is needed to break a copper wire having radius R. The force needed to break a copper wire of radius 2R will be

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Explanation

(c) Breaking Force = µ X Area of cross section of wire (πr2)

If radius of wire is double then breaking force will become four times.

The relationship between Young's modulus Y, Bulk modulus K and modulus of rigidity n is

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Explanation

(a)

 Y=3K1-2σY3K=1-2σand Y=2n1+σY2n=1+σOn doing 1+2×2-Y3K+Yn=3Yn+3K3nK=3Y=9nKn+3K

If x longitudinal strain is produced in a wire of Young's modulus y, then energy stored in the material of the wire per unit volume is-

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Explanation

(d) Energy stored per unit volume =12×Stress×Strain

     =12×Young's modulus×Strain2=12×y×x2

The Young's modulus of a rubber string 8 cm long and density 1.5 kg/m3 is 5×108 N/m2, is suspended on the ceiling in a room. The increase in length due to its own weight will be

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Explanation

(b) l=L2dg2Y=8×10-222×5×108=9.6×10-11m

A and B are two wires of same material. The radius of A is twice that of B. They are stretched by the same load. Then the stress on B is

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Explanation

(b) 

Stress=forceArea  Stress1πr2SBSA=rArB2=22SB=4SA

If the length of a wire is reduced to half, then it can hold the ......... load

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Explanation

(b) Breaking force  Area of cross section of wire

i.e. load hold by the wire does not depend upon the length of the wire

Why the spring is made up of steel in comparison of copper

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Explanation

(c)

Springs are designed based on the property of elasticity. In the spring the restoring force develops due to deformation. This deformation depends on the elasticity of a material. In the given materials steel is more elastic than copper. So steel is preferred to manufacture a spring.

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