NEET Practice Questions (MCQs) with Answers & Solutions

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If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of a mass of gas, when the volume changes from V to 2V constant pressure p, is 

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Explanation

ΔU=μCVΔT=nRγ1ΔT

ΔU=PΔV(γ1)=P(2VV)γ1=PV(γ1)

If heat given to a system is 6 kcal and work done is 6 kJ. Then the change in internal energy is :

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Explanation

ΔQ=ΔU+ΔWΔU=ΔQΔW

=6×4.186=19.08kJ

19.1kJ

A monoatomic gas of n-moles is heated from temperature T1 to T2 under two different conditions (i) at constant volume and (ii) at constant pressure. The change in internal energy of the gas is 

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Explanation

Change in internal energy ΔU=μCV ΔT

it doesn’t depend upon type of process. Actually it is a state function

Can two isothermal curves cut each other

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Explanation

If isothermal curves cut each other then at equilibrium two temperature will be there which is impossible.

A vessel containing 5 litres of a gas at 0.8 m pressure is connected to an evacuated vessel of volume 3 litres. The resultant pressure inside will be (assuming whole system to be isolated) 

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Explanation

0.8×5=P×(3+5)P=0.5m

For an isothermal expansion of a perfect gas, the value of ΔPP is equal -

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Explanation

Differentiate PV = constant w.r.t V

PΔV+VΔP=0ΔPP=ΔVV

If a gas is heated at constant pressure, its isothermal compressibility 

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Explanation

Eθ=P, if P = constant, Eθ=constant

In isothermal expansion, the pressure is determined by -

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Explanation

For such a case, pressure =1Compressibility

The isothermal bulk modulus of a perfect gas at normal pressure is -

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Explanation

Eθ=P=1.013×105N/m2

In an isothermal change, an ideal gas obeys -

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Explanation

In isothermal process, compressibility Eθ = ρ.

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