NEET Practice Questions (MCQs) with Answers & Solutions

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A string of length L and mass M hangs freely from a fixed point. Then the velocity of transverse waves along the string at a distance x from the free end is

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Explanation

The velocity of transverse waves along a stretched string depends on the tension in the string. The tension at a distance x from the free end is given by T = Mgx/L. Therefore, the velocity v = sqrt(T/μ) = sqrt(gx), where μ is the mass per unit length of the string.

Three waves of equal frequency having amplitudes 10 μm, 4 μm and 7 μm arrive at a given point with a successive phase difference of π2. The amplitude of the resulting wave in μm is given by 

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Explanation

Wave 1 and 3 reach out of phase. Hence resultant phase difference between them is π.

∴ Resultant amplitude of 1 and 3 = 10 – 7 = 3 μm

This wave has a phase difference of π2 with 4 μm

∴ Resultant amplitude = 32+42=5  μm

An organ pipe is closed at one end has a fundamental frequency of 1500 Hz. The maximum number of overtones generated by this pipe which a normal person can hear is : 

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Explanation

The critical hearing frequency for a person is 20,000Hz.

If a closed pipe vibrate in Nth mode, then the frequency of vibration n=(2N1)v4l=(2N1)n1

(where n1 = fundamental frequency of vibration)

Hence, 20,000 =(2N1)×1500N=7.17

Also, in a closed pipe;

Number of overtones = (No. of the mode of vibration) – 1

= 7 – 1 = 6.

An electric dipole is in unstable equilibrium in the uniform electric field. The angle between its dipole moment and the electric field is

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Explanation

4.

U = -PE cos θ

For unstable equilibrium electric dipole moment opposite to the electric field vector

i.e. θ = 180°

 maximum

So θ = π =  180°

A particle of mass m and charge q is at rest. If it is moved with velocity 3c2 where c is speed of light in vacuum, then its charge will become/remain

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Explanation

Charged be invarient quantity.

A charge q is to be divided on two small conducting spheres. What should be the value of charges on the spheres so that when placed at a certain distance apart, the repulsion force between them is maximum

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Explanation

Let the charge on one sphere=xThen, charge on other sphere=q-xForce between the spheres:F=kx(q-x)r2=k(qx-x2)r2For maximum force between the spheres:dFdx=0q-2x=0x=q2

You are traveling in a car during a thunderstorm. In order to protect yourself from lightning, you would prefer to

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Explanation

Due to electrostatic shielding.

If a soap bubble is given some charge, then its radius

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An electric dipole of dipole moment p is placed in an electric field of intensity E such that angle between electric field and dipole moment is θ. Assuming that the potential energy of the dipole is zero when θ=0°, the potential energy of the dipole will be

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Explanation

U=pECosθ1-Cosθ2Uf-Ui = pE Cosθ1-Cosθ2      θ1=0°    Ui=0 According to question      Uf=pE Cos0°-Cosθ      Uf=pE1-Cosθ

A point charge q is placed over a horizontal square of side L at a normal distance of L/4 from its centre. Electric flux through the square is 

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