Blog Log in Get Started Free

NEET Practice Questions (MCQs) with Answers & Solutions

Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Language English हिंदी

● ● ● ● ●

Two charges each of 1 coulomb are at a distance 1 km apart, the force between them is

9 × 10³ Newton

9 × 10^–3 Newton

1.1 × 10^–4 Newton

10⁴ Newton

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$F = \frac{k Q^{2}}{r^{2}} = 9 \times 10^{9} \times 1^{2} \times \frac{1}{{(1000)}^{2}} = 9 \times 10^{3} N$

● ● ● ● ●

+2C and +6C two charges are repelling each other with a force of 12 N. If each charge is given –2C of charge, then the value of the force will be

4 N (Attractive)

4 N (Repulsive)

8 N (Repulsive)

Zero

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Resultant charges after adding the – 2C be $(- 2 + 2) = 0$ and $(- 2 + 6) = + 4 C$

⇒ F $= \frac{k Q_{1} Q_{2}}{r^{2}} = k \times \frac{0 \times 4}{r^{2}} = 0$

● ● ● ● ●

Force of attraction between two point charges Q and – Q separated by d meter is F_e. When these charges are placed on two identical spheres of radius R = 0.3 d whose centres are d meter apart, the force of attraction between them is

Greater than F_e

Equal to F_e

Less than F_e

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Separation between the spheres is not too large as compared to their radius so due to induction effect redistribution of charge takes place. Hence effective charge separation decreases so force increases.

● ● ● ● ●

One metallic sphere A is given positive charge whereas another identical metallic sphere B of exactly same mass as of A is given equal amount of negative charge. Then

Mass of A and mass of B is the same

Mass of A is more

Mass of B is less

Mass of B is more

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Negative charge means excess of electron which increases the mass of sphere B.

● ● ● ● ●

The force between two charges 0.06 m apart is 5 N. If each charge is moved towards the other by 0.01 m, then the force between them will become

7.20 N

11.25 N

22.50 N

45.00 N

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$F \propto \frac{1}{r^{2}} \Rightarrow \frac{F_{1}}{F_{2}} = {(\frac{r_{2}}{r_{1}})}^{2}$

⇒ $\frac{5}{F_{2}} = {(\frac{0 .04}{0 .06})}^{2} = F_{2} = 11 .25 N$

● ● ● ● ●

When 10¹⁹ electrons are removed from a neutral metal plate, the electric charge on it is

–1.6 C

+1.6 C

10⁺¹⁹ C

10^–19 C

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

By using $Q = n e \Rightarrow Q = 10^{19} \times 1 .6 \times 10^{- 19}$ = +1.6 C.

● ● ● ● ●

Two charges each equal to 2μC are 0.5m apart. If both of them exist inside vacuum, then the force between them is

1.89 N

2.44 N

0.144 N

3.144 N

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

By using $F = 9 \times 10^{9} . \frac{Q^{2}}{r^{2}}$

⇒ $F = 9 \times 10^{9} . \frac{{(2 \times 10^{- 6})}^{2}}{{(0 .5)}^{2}} = 0 .144 N$

● ● ● ● ●

An electron is moving around the nucleus of a hydrogen atom in a circular orbit of radius r. The Coulomb force $\vec{F}$ on electron is (Where $K = \frac{1}{4 π ε_{0}}$ )

$- K \frac{e^{2}}{r^{3}} \hat{r}$

$K \frac{e^{2}}{r^{3}} \vec{r}$

$- K \frac{e^{2}}{r^{3}} \vec{r}$

$K \frac{e^{2}}{r^{2}} \hat{r}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$\vec{F} = - k \frac{e^{2}}{r^{2}} \hat{r} (V e c t o r f o r m) = - k . \frac{e^{2}}{r^{3}} \vec{r}$ $(∵ \hat{r} = \frac{\vec{r}}{r})$

● ● ● ● ●

Five balls numbered 1 to 5 are suspended using separate threads. Pairs (1, 2), (2, 4), and (4, 1) show electrostatic attraction, while pair (2, 3) and (4, 5) show repulsion. Therefore ball 1 must be

Positively charged

Negatively charged

Neutral

Made of metal

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

(2, 3) and (4, 5) repel each other. It is clear that 2, 3, 4, and 5 are charged bodies. Let (2, 3) have +ve charge and (4, 5) have -ve charge. (1, 2) attract each other. That means ball 1 has -ve charge. But (1, 4) also attract each other. So ball 1 should be neutral. In that case, only, ball 1 can be attracted by both 2 and 4.It means be ball one has no charge so it must negatively charge.

● ● ● ● ●

Equal charges q are placed at the four corners A, B, C, D of a square of length a. The magnitude of the force on the charge at B will be

$\frac{3 q^{2}}{4 π ε_{0} a^{2}}$

$\frac{4 q^{2}}{4 π ε_{0} a^{2}}$

$(\frac{1 + 2 \sqrt{2}}{2}) \frac{q^{2}}{4 π ε_{0} a^{2}}$

$(2 + \frac{1}{\sqrt{2}}) \frac{q^{2}}{4 π ε_{0} a^{2}}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

The force on the charge at B is the vector sum of the forces due to the charges at A, C, and D. The force due to the charge at A is zero as it is along the same line. The forces due to the charges at C and D have equal magnitudes and make an angle of 45Â° with the line BC and BD respectively. Therefore, the resultant force has a magnitude (1 + 2âˆš2) times the individual force.

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.