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Calculate the area of the plates of a one farad parallel plate capacitor if the separation between plates is 1 mm and plates are in a vacuum.

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Explanation

For a parallel plate capacitor  C=ε0 Ad

  A=Cdε0=1×10-38.85×10-12 =1.13×108 m2

This corresponds to the area of a square of side 10.6 km which shows that one farad is a very large unit of capacitance. 

Assertion : A particle A of mass m and charge Q moves directly towards a fixed particle B, which

                  has charge Q. The speed of A is v when it is far away from B. The minimum separation

                  between the particles is proportional to Q2.

Reason : Total energy remains conserved.

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Explanation

According to law of conservation of energy,

12mv2 = KQ2xmin      or      xmin=2KQ2mv2

Assertion : Potential difference between two points lying in a uniform electric field may be equal

                  to zero.

Reason : Points of line normal to electric field is equipotential line. 

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Explanation

If two points, lying on a line normal to the direction of electric field, are considered equipotential then the potential difference between these two points will be equal to zero.

Assertion :  At a distance r from a +ve charged particle potential is V and electric field strength is E.

                   Then graph between V2E is straight line.

Reason : For a point charge V2E=q4π0

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Explanation

For a point charge E=14π0qr2 ;    V=14π0qr

Assertion :  Each of the plates of a parallel-plate capacitor is given equal positive charge Q. The

                   charges on the facing surfaces will be same. 

Reason : A negative charge (–Q) will be induced on each of the facing surfaces.

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Explanation

The charge on each of two facing surfaces will be zero.

Assertion : Electric potential is a property of an electric field, regardless of whether a charged

                  object has been placed in that field.

Reason : Potential depends on test charge. 

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Explanation

Potential is a property of electric field and it is independent on test charge.

Assertion : Electric potential and electric potential energy are different quantities.

Reason :  For a system of positive test charge and point charge electric potential energy = electric potential. 

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Explanation

Potential and potential energy are different quantities and cannot be equated.

Assertion : The component of E in any direction is the negative of the rate of change of the

                   electric potential with distance in that direction. 

Reason :  Potential gradient in any direction at a point gives total electric field at that point. 

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Explanation

E=-vxi^+vyj^+vzk^

Assertion : Two equipotential surfaces cannot cut each other. 

Reason : Two equipotential surfaces are parallel to each other.

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Explanation

Two equipotential surfaces are not necessarily parallel to each other.

A battery of internal resistance r, when connected across 2Ω resistor supplies a current of 4A, when the same battery is connected across a 5Ω resistor, it supplies a current of 2A. The value of r is  

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Explanation

4=Er+2  ...12=Er+5   ...2r=1Ω

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