Practice free Amines (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
Identify the product in the following reaction:
Sandmeyer with Cu₂Br₂/HBr gives bromobenzene; Mg/dry ether forms PhMgBr; H₂O protonates Grignard → benzene.
Which of the following reactions will NOT give primary amine as the product?
Isocyanide reduction (C) gives a secondary amine (CH₃–NH–CH₃). Others give 1° amines.
Given below are two statements:
Statement I: Aniline does not undergo Friedel-Crafts alkylation reaction.
Statement II: Aniline cannot be prepared through Gabriel synthesis.
In the light of the above statements, choose the correct answer from the options given below:
AlCl₃ complexes with –NH₂ lone pair, deactivating the ring (Statement I true). Gabriel synthesis gives primary aliphatic amines only — aryl halides do not undergo S$_\text{N}$2 with phthalimide ion (Statement II true).
Identify the major product C formed in the following reaction sequence:
$CH_3\text{-}CH_2\text{-}CH_2\text{-}I \xrightarrow{NaCN} A \xrightarrow[\text{Partial hydrolysis}]{OH^-} B \xrightarrow{NaOH/Br_2} C\ (\text{major})$
NaCN substitution → butanenitrile (A); partial hydrolysis → butanamide (B); Hofmann bromamide → 1° amine with one less C → propylamine (C).
The correct order of decreasing basic strength of the given amines is:
Aliphatic amines are more basic than aromatic. Secondary (N-ethylethanamine) > primary aliphatic (ethanamine) > N-methylaniline > aniline (benzenamine).
Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273–278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer:
Both statements are correct: benzenediazonium chloride is made at 273–278 K and decomposes when dry; iodobenzene is conveniently made via the diazonium salt + KI.
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