Basic Principles of Orgainc Chemistry MCQs for NEET — Chemistry Questions with Answers

(c) -N> >NH> -NH₂.

(d) NH₄CNO is functional isomer of urea.

(b) The possible carbocations are (CH₃)₃  C⁺ (CH₃)₂CH C+ H₂, CH₃CH₂CH₂ C+ H₂ and CH₃CH₂ C+ HCH₃.

(c) CH3C||CH2C||OC2H5 â‡Œ CH3C|=CH.COOC2H5          O       O                           OH

(a) CH3CH2CH2CH3→    hv        Cl2    CH3CHClCH2CH3 + CH3CH2CH2CH2Cl

(b) C₆H₅-C||O-CH₃ â‡ŒC₆H₅ -C|OH=CH2 In rest of all migration of H is not possible.

${\mathrm{C}}_3{\mathrm{H}}_9\mathrm{N}$

1. $$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{NH}}_2 \\ 1-\mathrm{Aminopropane} \end{gathered}$$

2. $$\begin{gathered} {\mathrm{CH}}_3-\underset{{\mathrm{NH}}_2}{\underset{|}{\mathrm{CH}}}-{\mathrm{CH}}_3 \\ 2-\mathrm{Aminopropane} \end{gathered}$$

3. $$\begin{gathered} {\mathrm{CH}}_3-\mathrm{NH}-{\mathrm{CH}}_2{\mathrm{CH}}_3 \\ \mathrm{Methyl} \mathrm{Amino} \mathrm{ethane} \end{gathered}$$

4. $$\begin{gathered} {\mathrm{CH}}_3-\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{N}}}-{\mathrm{CH}}_3 \\ \mathrm{Dimethyl} \mathrm{Amino} \mathrm{methane} \end{gathered}$$

(c) CHO C^*HOHCH₂OH has one asymmetric carbon (*).

Tartaric acid contains two asymmetric carbon atoms, leading to the existence of stereoisomers. It exists in three stereoisomeric forms: dextro, levo, and meso. Acetic acid, oxalic acid, and formic acid do not have any asymmetric carbon atoms, hence they do not exhibit stereoisomerism.