Classification of elements and Periodicity in properties MCQs for NEET — Chemistry Questions with Answers

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Actinide contraction is mainly related to :-

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Atomic radius of Be, O, C, N, B are respectively (in pm) :-

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Explanation

radius decreases from left to right in P.T

First four IP values of an element are 19, 190, 230 and 260 eV/atom. Element belongs to:-

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Explanation

IEO.S

A large difference between fifth and sixth ionisation energies indicate the element having :-

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Explanation

group 15, has I.E6 >>>>I.E 5

If atomic number of an element of He-family is Z then which of the following atomic number will highest IP?

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Explanation

n-1  = grp 17

n - 2 = grp 16

n + 1 = grp 1

n + 2 = grp 2

so grp 17  will have highest I.E

The element having very high electron affinity but zero ionisation enthalpy is :-

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The pair of which addition of 2nd electron in both the atoms are endothermic :-

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Explanation

Addition of 2nd electron is always endothermic.

In which of the following options the order of arrangement does not agree with the variation of property indicated against it?

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Explanation



(a)

For option (a)

First ionisation energy is the energy required to remove an electron from outermost shell.

Hence, correct order is B < C < O < N.

For option (b)

Electron gain enthalpy is the energy required to gain an electron in the outermost shell.

Hence, the correct order is I < Br < F < Cl.

For option (c)

As we move down the group in alkali metal, metallic radius increases Li < Na < K < Rb.

For option (d)

In case of isoelectronic species, as positive charge decreases or negative charge increases the ionic size of the species increases and vice-versa Al3+ < Mg2+ < Na+ <F- .

The species Ar, K+ and Ca2+ contain the same number of electrons. In which order do their radii increase?

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Explanation

            Ca2+ < K+ < Ar
Ar , K+ and Ca2+ are isoelectronic i.e. with same number of electrons. 18. For isoelectronic species ionic radii decreases with increase in effective (relative) positive charge. Also Ar, K and Ca belong to the same period (3rd period).

The formation of the oxide ion O2-(g), from oxygen atom requires first an exothermic and then an endothermic step as shown
below,

O(g) + e-           O-(g); fH° = -141kJmol-1O-(g) +e-           O2-(g); fH° = +780 kJ mlo-1

Thus, process of formation of O2- in gas phase is unfavourable even though O2- is isoelectronic with neon. It is due to the fact that

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Explanation

(a) Since, electron repulsion predominate over the stability gained by achieving noble gas configuration. Hence, fomation of O2- in gas phase is unfavourable.

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