Classification of elements and Periodicity in properties MCQs for NEET — Chemistry Questions with Answers

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Which of the following pairs correctly represents elements exhibiting diagonal relationship, as discussed in the context of anomalous properties of second-period elements?

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Explanation

The context states, 'In fact the behaviour of lithium and beryllium is more similar with the second element of the following group i.e., magnesium and aluminium, respectively. This sort of similarity is commonly referred to as diagonal relationship in the periodic properties.' Therefore, Li and Mg exhibit a diagonal relationship.

Consider the following statements regarding the first element of group 13 (Boron) and its anomalous properties: I. Boron forms predominantly ionic compounds. II. Boron has a small size and high electronegativity. III. Boron has only 2s and 2p orbitals available for bonding. Which of the above statements are correct?

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Explanation

The first element of group 13 (Boron) exhibits anomalous properties due to its small size, large charge/radius ratio, and high electronegativity (II). Like other second-period elements, it only has 2s and 2p orbitals for bonding (III), leading to limited valency and orbital expansion. Unlike its heavier congeners which tend to form more ionic compounds, Boron forms compounds with more covalent character due to its high polarizing power. Thus, statement I is incorrect.

The formula of the oxide formed by Lithium is Liâ‚‚O, while oxides of heavier alkali metals like Sodium are also represented as Naâ‚‚O. However, Lithium's behavior shows pronounced covalent character. This implies that Liâ‚‚O is:

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Explanation

The NCERT states, 'For example, lithium unlike other alkali metals... form compounds with pronounced covalent character; the other members of these groups predominantly form ionic compounds.' Therefore, Liâ‚‚O would exhibit more covalent character compared to Naâ‚‚O, which is predominantly ionic.

Which of the following is a direct consequence of the 'small size' and 'large charge/radius ratio' of second-period elements?

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Explanation

The NCERT states that 'lithium unlike other alkali metals, and beryllium unlike other alkaline earth metals, form compounds with pronounced covalent character'. This anomalous behavior, including covalent character, is attributed to their 'small size, large charge/radius ratio and high electronegativity'.

The valence of representative elements is usually equal to the number of electrons in the outermost orbitals or eight minus the number of outermost electrons. How does the anomalous behavior of second-period elements affect this trend specifically for bonding capacity?

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Explanation

The text states, 'the first member of group has only four valence orbitals (2s and 2p) available for bonding'. This means that second-period elements cannot expand their octet, thus restricting their maximum covalency to four (one s and three p orbitals). The absence of d-orbitals prevents higher covalency.

Considering the periodic trends, which statement about element 'X' from the second period and 'Y' from the third period (both in the same group, and 'X' being the first element) is generally CORRECT regarding their chemical properties?

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Explanation

According to the NCERT, 'The anomalous behaviour is attributed to their small size, large charge/radius ratio and high electronegativity of the elements.' These factors lead to a greater tendency for covalent bonding in second-period elements compared to their heavier group members (Y), which tend to form more ionic compounds due to larger size and lower electronegativity. Atomic radius increases down a group, and electronegativity decreases down a group. Second-period elements have fewer valence orbitals (2s, 2p) than third-period elements (3s, 3p, 3d, where 3d orbitals can be utilized).

What is the IUPAC numerical root for the digit '5' used in naming elements with atomic number greater than 100?

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Explanation

According to Table 3.4 'Notation for IUPAC nomenclature of Elements', the numerical root for the digit '5' is 'pent'.

Which of the following temporary IUPAC names correctly corresponds to its atomic number according to the given nomenclature rules?

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Explanation

For Z=108: un (1), nil (0), oct (8), and 'ium' suffix, making it Unniloctium. Let's check others: Z=109 is Unnilennium (not Ununennium), Z=106 is Unnilhexium (not Unnilseptium), Z=111 is Unununnium (not Ununbium).

The primary reason IUPAC established a systematic temporary nomenclature for elements with Z > 100 was to:

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Explanation

The NCERT text states: 'To avoid such problems, the IUPAC has made recommendation that until a new element’s discovery is proved, and its name is officially recognised, a systematic nomenclature be derived directly from the atomic number of the element...'. This directly addresses the issue of conflicting claims, such as the American and Soviet claims for element 104.

If an element has the temporary IUPAC symbol 'Uuh', what is its atomic number?

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Explanation

From Table 3.4, 'U' stands for 'un' (1), 'u' for 'un' (1), and 'h' for 'hex' (6). Therefore, 'Uuh' corresponds to the atomic number 116. This aligns with Table 3.5 which lists Ununhexium (Uuh) for Z=116.

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