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D & F Block Elements MCQs for NEET — Chemistry Questions with Answers

Practice free D & F Block Elements (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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Which of the following statements about the acidity of metal oxides is correct?

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Explanation

$V_2O_5$ is, however, amphoteric though mainly acidic and it gives $VO_4^{3–}$ as well as $VO_2^+$ salts. In vanadium there is gradual change from the basic $V_2O_3$ to less basic $V_2O_4$ and to amphoteric $V_2O_5$. (NCERT, Chapter: The d - and f - Block Elements, Page 105)

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Which of the following transition elements does NOT exhibit variable oxidation states?

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Explanation

Scandium (Z = 21) does not exhibit variable oxidation states. (NCERT, Chapter: The d - and f - Block Elements, Page 99)

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In the 3d series, the ability of fluorine to stabilize the highest oxidation state is due to:

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Explanation

The ability of fluorine to stabilise the highest oxidation state is due to either higher lattice energy as in the case of $CoF_3$, or higher bond enthalpy terms for the higher covalent compounds, e.g., $VF_5$ and $CrF_6$. (NCERT, Chapter: The d - and f - Block Elements, Page 99)

NEET 2023
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The stability of Cu²⁺ is more than Cu⁺ salts in aqueous solution due to:

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Explanation

Cu²⁺ has very large hydration enthalpy that overcompensates the higher 2nd IE.

NEET 2023
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Which of the following statements are INCORRECT?

A. All the transition metals except scandium form MO oxides which are ionic. B. The highest oxidation number corresponding to the group number in transition metal oxides is attained in Sc₂O₃ to Mn₂O₇. C. Basic character increases from V₂O₃ to V₂O₄ to V₂O₅. D. V₂O₄ dissolves in acids to give VO₄³⁻ salts. E. CrO is basic but Cr₂O₃ is amphoteric.

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Explanation

C wrong (basicity decreases as oxidation number rises). D wrong (V₂O₄ + acid gives $VO^{2+}$, not VO₄³⁻).

NEET 2024
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The $E^\circ$ value for the $\text{Mn}^{3+}/\text{Mn}^{2+}$ couple is more positive than that of $\text{Cr}^{3+}/\text{Cr}^{2+}$ or $\text{Fe}^{3+}/\text{Fe}^{2+}$ due to change of:

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Explanation

Mn³⁺ ($d^4$) → Mn²⁺ ($d^5$, half-filled, stable) — large favourable change, hence more positive $E^\circ$.

NEET 2024
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'Spin only' magnetic moment is same for which of the following ions?

A. $Ti^{3+}$ B. $Cr^{2+}$ C. $Mn^{2+}$ D. $Fe^{2+}$ E. $Sc^{3+}$

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Explanation

Unpaired e⁻: Ti³⁺ ($d^1$, 1), Cr²⁺ ($d^4$, 4), Mn²⁺ ($d^5$, 5), Fe²⁺ ($d^6$, 4), Sc³⁺ ($d^0$, 0). B and D both have 4 unpaired e⁻.

NEET 2024
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The pair of lanthanoid ions which are diamagnetic is

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Explanation

$Ce^{4+}$ is $f^0$ and $Yb^{2+}$ is $f^{14}$ — both have no unpaired electrons.

NEET 2024
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During the preparation of Mohr's salt solution (Ferrous ammonium sulphate), which of the following acid is added to prevent hydrolysis of $\text{Fe}^{2+}$ ion?

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Explanation

Dilute H₂SO₄ suppresses hydrolysis of Fe²⁺ without introducing foreign cations/anions or oxidising Fe²⁺.

NEET 2025
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Given below are two statements:

Statement I: Ferromagnetism is considered as an extreme form of paramagnetism.

Statement II: The number of unpaired electrons in a $\text{Cr}^{2+}$ ion (Z = 24) is the same as that of a $\text{Nd}^{3+}$ ion (Z = 60).

In the light of the above statements, choose the correct answer:

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Explanation

Ferromagnetism is an extreme form of paramagnetism (I true). $\text{Cr}^{2+}$ ($3d^4$) has 4 unpaired electrons while $\text{Nd}^{3+}$ ($4f^3$) has 3 — not equal (II false).

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