Match List I with List II.
| List I (Conversion) | List II (Number of Faraday required) |
|---|---|
| A. 1 mol of $H_2O$ to $O_2$ | I. 3F |
| B. 1 mol of $MnO_4^{-}$ to $Mn^{2+}$ | II. 2F |
| C. 1.5 mol of Ca from molten $CaCl_2$ | III. 1F |
| D. 1 mol of FeO to $Fe_2O_3$ | IV. 5F |
Choose the correct answer from the options given below:
You've reached today's free limit of 20 questions.
Log in to keep practising for free.
Explanation
A: $2H_2O \to O_2 + 4H^+ + 4e^-$, 1 mol → 2F. B: Mn $+7 \to +2$ → 5F. C: $Ca^{2+} + 2e^- \to Ca$, 1.5 mol → 3F. D: $Fe^{2+} \to Fe^{3+}$, 1 mol → 1F.