Hydrocarbons MCQs for NEET — Chemistry Questions with Answers

Practice free Hydrocarbons (Chemistry) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Clear Register free for difficulty & keyword filters
NEET 2024
● ● ● ● ●

Identify the correct reagents that would bring about the following transformation.

Ph–CH₂–CH=CH₂ → Ph–CH₂–CH₂–CHO

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Anti-Markovnikov OH placement needs hydroboration-oxidation, then PCC oxidises the primary alcohol selectively to the aldehyde (CrO₃ would over-oxidise to the carboxylic acid).

NEET 2024
● ● ● ● ●

A compound with a molecular formula of $C_6H_{14}$ has two tertiary carbons. Its IUPAC name is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$(CH_3)_2CH\text{-}CH(CH_3)_2$ has two adjacent tertiary carbons.

NEET 2024
● ● ● ● ●

For the given reaction: Ph–CH=CH–Ph $\xrightarrow{KMnO_4/H^+}$ 'P' (major product). 'P' is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Hot acidic KMnO₄ cleaves the C=C oxidatively; each side becomes a –COOH on the phenyl ring → benzoic acid.

NEET 2025
● ● ● ● ●

Predict the major product "P" in the following sequence of reactions: 1-methylcyclopentene $\xrightarrow{\text{(i) HBr, benzoyl peroxide}}\xrightarrow{\text{(ii) KCN}}\xrightarrow{\text{(iii) Na(Hg)/C}_2\text{H}_5\text{OH}}$ P (Major)

H₃C
You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(i) HBr with peroxide adds Br anti-Markovnikov to the less-substituted carbon (C2). (ii) KCN does SN2 → nitrile at C2. (iii) Na(Hg)/EtOH reduces –CN to –CH₂NH₂. Product: CH₃ and –CH₂NH₂ on adjacent ring carbons.

NEET 2025
● ● ● ● ●

Which one of the following reactions does NOT give benzene as the product?

COONa(1) PhCOONa + sodalime, Δ(2) n-hexane / Mo₂O₃, 773 K(3) HC≡CH / red-hot Fe, 873 KN₂⁺Cl⁻(4) PhN₂⁺Cl⁻ + H₂O, warm
You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Benzene diazonium chloride with warm water gives phenol (and N₂), not benzene. The other three (decarboxylation, aromatization of hexane, cyclic trimerization of ethyne) all give benzene.

NEET 2025
● ● ● ● ●

How many products (including stereoisomers) are expected from monochlorination of the following compound: $(\text{CH}_3)_2\text{CH–CH}_2\text{–CH}_3$ (2-methylbutane)?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Four constitutional monochloro products; two of them (1-chloro-2-methylbutane and 2-chloro-3-methylbutane) contain a stereocentre giving a pair of enantiomers each. Total $= 2+1+2+1 = 6$.

NEET 2025
● ● ● ● ●

Which one of the following compounds does NOT decolourize bromine water?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Cyclohexane is a saturated hydrocarbon and does not react with bromine water. Phenol and aniline brominate the ring; styrene adds across the C=C.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Hydrocarbons question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.