Purification and Characteristics of Organic Compounds MCQs for NEET — Chemistry Questions with Answers

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While detecting phosphorous in organic compound yellow colour is obtained due to the formation of

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Explanation

The yellow color observed during the detection of phosphorus in an organic compound is due to the formation of ammonium phosphomolybdate, which has the chemical formula \((NH_4)_3PO_4 \cdot 12MoO_3\). This compound is a characteristic yellow precipitate that confirms the presence of phosphorus.

0.306 gm of the silver salt of a monobasic organic acid yeilds 0.216gm of Silver on ignition. Find molecular weight of the acid.

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Explanation

$ MW = { 108 \times 0.306 \over 0.216 } - 107 = 46 $

1.026gm of the silver salt of a tribasic organic acid gave an ignition 0.648gm silver. Find molecular weight of the acid.

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Explanation

To find the molecular weight of the acid, we use the mass of the silver salt and the mass of silver obtained upon ignition. The tribasic acid forms a silver salt with 3 Ag atoms. The formula weight of silver (Ag) is 108 g/mol. The mass of silver in the salt is 0.648 g, which corresponds to 3 moles of Ag (since it's a tribasic salt). Therefore, the equivalent weight of the acid can be calculated as follows: \((1.026 / 0.648) imes 108 / 3 = 192\). Thus, the molecular weight of the acid is 192 g/mol.

Chromatography is used for the purification of

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Explanation

Chromatography is a versatile technique used for the separation and purification of various substances. It can be used to purify solids, liquids, and gases. This is because chromatography relies on the differential partitioning between the mobile and stationary phases, making it effective for a wide range of substances.

The presence of halogen in an organic compound is detected by

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Explanation

Beilstein’s test is used for the detection of halogens in an organic compound. In this test, a copper wire is heated in a flame until it stops producing a green flame. Then the wire is dipped into the organic compound and reheated in the flame. If a green flame reappears, it indicates the presence of halogen in the compound.

How will you separate a solution of benzene and chloroform ?

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Explanation

To separate a solution of benzene and chloroform, distillation is the most appropriate method. Benzene and chloroform have different boiling points (benzene boils at 80.1°C, while chloroform boils at 61.2°C). Distillation allows them to be separated based on these differences in boiling points.

Which method can be used to separate a mixture of KCl and $ KClO_ 3$ ?

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Explanation

Fractional Crystallisation is the method used to separate a mixture of KCl and $KClO_3$. This technique is based on the different solubilities of KCl and $KClO_3$ in water. By carefully controlling the temperature, one can selectively crystallise one component from the mixture, leaving the other in solution.

Middleton’s test is used to detect

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Explanation

Middleton’s test is used to detect Sulfur (S). This test involves converting sulfur compounds into sulfur dioxide ($SO_2$) and then using barium chloride to detect the presence of sulfur dioxide by forming a white precipitate of barium sulfate.

An organic compound weighing 4.337mg yielded 10.35mg of $ CO_2 and 3.42mg of H_2O$ on oxidation with CuO. Calculate the empirical formula of the compound.

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An organic compound contains 69% C and 4.8% H, the remainder being oxygen. Calculate the masses of $ CO_2 and H_2O $ produced when 0.2gm of this substance is completely combusted.

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