Chemistry MCQs for NEET — Practice Questions with Answers

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What is the value of $ E_{Mg | Mg ^{2+} _{(0.5 M)}} at 25 ^\circ C ? ( E^ \circ _{Mg|Mg ^{ 2+} = 2.36 V. ) $

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If potential of the cell formed by connecting half cell Ag | Ag+ and Al | Al3+ is 2.546V then what is the std. cell potential of the cell at 250C?

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For cell $ Mg | Mg^{2+} _{(0.005M)} â•‘ Ag^+_{0.04M} | Ag $ which of the following option is correct for the value of Q related to n ?

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For the cell $ Co | Co^ {2+} _{(0.04M)} | Cl^-_{(0.1M)}| Cl_{2(g,1.0 bar)}| Pt $ which of the following option is correct for the value of Q related to the value of n? (a) n = 1 (b) n = 2 (c) n = 3 (d) n = 4 (1) $ Q = 4.0 \times 10 ^ {-4} M^3 $ (2) $ Q = 8 M ^ {-3/2} $ (3) $ Q = 8.0 \times 10 ^ {-6} M ^ {9/2} $ (4) $ Q = 2 M ^ {-1/2} $ (5) $ Q = 4 M^{-1} $ (6) $ Q = 1.6 × 10^{-7} M^6 $ (7) $ Q = 0.002 M ^ {3/2} $ (8) $ Q = 16 M ^ {-2} $

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For the cell $ Pt | Br_{2(g,1.0 bar)} | Br ^ - _{(0.5M)} || Au ^{3+}_{(0.4M)} | Au value of Q = 20M^{-4} $ then what is the appropriate value of n?

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Explanation

For the given cell: Pt | Br₂(g, 1.0 bar) | Br⁻(0.5M) || Au³⁺(0.4M) | Au, the overall cell reaction is: 3/2 Br₂(g) + 3e⁻ = 3Br⁻ (reduction at cathode) and Au³⁺ + 3e⁻ = Au (reduction at anode). The value of n, which represents the number of electrons transferred, is 3 for this balanced reaction.

If temperature of the cell $ Mg | Mg^{2+}_{(0.005M)} || Ag^+_{(0.04M)} | Ag $ increases then what changes observed in the cell potential of the cell?

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Explanation

For the given cell: Mg | Mg²⁺(0.005M) || Ag⁺(0.04M) | Ag, an increase in temperature will decrease the cell potential. This is because the standard reduction potentials of both half-reactions (Mg²⁺/Mg and Ag⁺/Ag) decrease with increasing temperature, leading to a decrease in the overall cell potential.

If temperature of the cell $ Ni | Ni^{2+} _{0.05M} || Cu^{2+}_{(0.08M)} | Cu $ increases then what changes observed (0.05 M) in the cell potential of the cell?

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If temperature of the cell $ Fe | Fe^{2+}_{(xM)} || Cu^{2+} _{(0.08M)} | Cu $ decreases then theoritically cell potential of the cell increases then which value of x is possible?

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If temperature of the cell $ Zn | Zn^{2+}_{C_1} || Sn^{2+}_{C_2} | Sn (C_1 < C_2) $ decreases then theoritically cell potential what changes are observed in the cell potential of the cell?

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What is the equilibrium constant of the reaction taking place in the cell $ Zn | Zn^{2+}_{(C-1)} || Cu^{2+}_{(C-2)} | Cu at 25 ^\circ C? ( E ^ \circ _{Zn ^{2+} |Zn} = − 0.76 V., E ^\circ Cu ^{ 2+} | Cu= 0.34 V.)$

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Explanation

The equilibrium constant (K) of an electrochemical cell is related to the standard electrode potential (E°) by the equation: K = exp(nFE°/RT), where n is the number of electrons transferred, F is the Faraday constant, R is the gas constant, and T is the absolute temperature. Given E°(Zn²⁺/Zn) = -0.76 V and E°(Cu²⁺/Cu) = 0.34 V, we can calculate E° for the overall cell reaction: E°cell = E°cathode - E°anode = 0.34 V - (-0.76 V) = 1.10 V. Substituting the values, we get K = exp(2 × 96485 C/mol × 1.10 V / (8.314 J/mol·K × 298 K)) = 1.9413 × 10³⁷.

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