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What would be the elevation in boiling point of 0.1 m NaCl solution ? (Assume that Nacl dissociates completely)
$ For NaCl value of i= 2.0 $ $ \therefore \triangle Tb = i.m.Kb = 2 \times 0.1 \times Kb $ $ \therefore \triangle Tb = { Kb \over 5} $
Which of the following semipermeable membrane is best one ?
Cellophane is a semi-permeable membrane made from regenerated cellulose, which allows the passage of small molecules like water but prevents the passage of larger molecules, making it an effective semi-permeable membrane for various applications.
At constant temperature, binary ideal solution is formed by two liquids A and B. At equilibrium, mole-fraction of liquid B is 0.4 and vapour state mole-fraction of B is 0.25. $ P ^\circ B=40 mm$ , then at the same temperature, what will be the vapour pressure of pure liquid ‘A’ ?
$ X_A = 1 -X_B = 1 - 0.4 = 0.6 $ $ Y_A = 1 - Y_B = 1- 0.25 = 0.75 $ $ p_B = p^ \ circ _B \times X_B $ $ \therefore p_B = 40 \times 0.4 $ = 16 mm $ p_B = P_{total} \times Y_B $ $ \therefore 16 = P_{total} \times 0.25 $ $ \therefore P_{total} = 64 mm $ $ p_A = P_{total} \times Y_A = 64 \times 0.75 = 48 mm $ $ Now p_A = p ^ \circ _A \times X_A $ $ 48 = p ^ \circ _A \times 0.6 $ $ \therefre p ^ \circ _A =80 mm $
At constant temperature, 2 litres aqueous solution of each $ 0.2 M kcl and 0.3 M AlCl_3 $ are in contact with each other by semipermeable membrane. When osmosis stops, then, what mililitre water diffuses from semipermeable membrane to the other side ? (Assume that ionic solids dissociates completely in the aqueous solution)
Liquid present in RBC is isotonic with 0.91 % w/v solution of NaCl $ \therefore Morality of soluble particles in 0.91 \% w/v NaCl Solution $ $ = { 2 \times 1000 \times 0.91 \over 58.5 \times 100 } $ $ = 2 \times 0.1555 $ = 0.311 M
Which of the following solution is hypotonic with fluids in RBC ?(Assume that ionic solid substances completely dissociates in the solution)
To determine whether a solution is hypotonic or hypertonic compared to the fluids inside red blood cells (RBCs), we need to consider the concentration of solute particles. The normal osmotic pressure inside RBCs corresponds to a 0.9% NaCl solution, which is approximately 0.154 M NaCl. Therefore, any solution with a lower concentration than 0.154 M NaCl will be hypotonic to RBCs.
X M NaCl is isotonic with fluids present in RBC (Red Blood Corpusceles), then what would be the value of x ? (M.w. Of NaCl =58.5 gm/mole) (Assume that ionic solid substances completely dissociates in the solution)
Which of the following solution is hypotonic in comparison with the solution of 0.4 M glucose?
Which of the following solution is hypotonic in comparison with 0.15 M kCl solution ?(Assume that ionic solid substances completely dissociates in the solution)
The question is asking which solution is hypotonic (lower osmotic pressure) compared to 0.15 M KCl solution. Urea is a non-electrolyte and does not dissociate into ions, so its osmotic pressure is solely due to the number of particles present. 0.2 M urea solution will have a lower osmotic pressure than 0.15 M KCl solution, which dissociates into ions.
Which of the following solution is isotonic with fluid of RBC ? (For NaCl, i=2)
Which of the following solution is isotonic with fluid of RBC ? (For NaCl, 2=2)
The fluid inside RBCs is isotonic with 0.9% w/v NaCl solution. Since glucose is a non-electrolyte, 2.02% w/v glucose solution will have the same osmotic pressure as 0.9% w/v NaCl solution, making it isotonic with the RBC fluid.
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