How many electrons in Cu atom have (n + ) = 4
Chemistry MCQs for NEET — Practice Questions with Answers
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For a certain particle, it is found that uncertainty 1840 in velocity is reciprocal of uncertainty in position This implies that
Suggest two transitions in hydrogen spectrum for which wave number ratio is 108:7
The wave number ratio of 108:7 corresponds to the transitions 2 → 1 and 4 → 3 in the hydrogen spectrum. This can be calculated using the Rydberg formula, which relates the wavenumber to the energy levels involved in the transition.
The ratio of K.E. to P.E. of an electron in Bohr orbit of H like species is
$ K.E = { Ze ^ 2 \over 2 r } P.E = { Ze ^2 \over r } \therefore {K.E \over P.E} = { 1/2 \over -1 } = -1.2 $
For particles having same KE., the de-broglie wavelength is
In one joule of energy, the number of photon with wave number equal to is
$ E = h \nu = nh { c \over \lambda } = nhc \bar v \therefore now E = 1 , \bar v = x \therefore n = { 1 \over hcx } = ( hcx)^{-1} $
Which of the expression given below gives IE of H atoms in terms of Rydberg’s constant $ (R_H)$ ?
The expression $R_H hc$ gives the ionization energy (IE) of the hydrogen atom in terms of the Rydberg constant ($R_H$), Planck's constant ($h$), and the speed of light ($c$). This expression is derived from the Rydberg formula and represents the energy required to remove an electron from the ground state of the hydrogen atom.
One unpaired electron causes magnetic moment of 1.1 B.M. The magnetic moment of $ Fe^{+2} $ ion is
If numerical value of mass and velocity are equal then de-Broglie wave length in terms of K.E. is
If uncertainty in position and velocity are equal then uncertainty in momentum will be
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