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Chemistry MCQs for NEET — Practice Questions with Answers

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The radius of La³⁺ (at. no. 57) is 1.06 $\overset{°}{A}$ The radius of Lu³⁺ (at.no. 71) might be:

1.06 $\overset{°}{A}$

0.85 $\overset{°}{A}$

1.60 $\overset{°}{A}$

1.40 $\overset{°}{A}$

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Explanation

(b) Due to lanthanoid contraction

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Which of the following transition metal ions has the lowest density?

Copper

Nickel

Scandium

Zinc

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Explanation

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Ionic radii are

[2004]

inversely proportional to effective nuclear charge

inversely proportional to square of effective nuclear charge.

directly proportional to effective nuclear charge

directly proportional to square of effective nuclear charge

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Which one of the following has the highest melting point?

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Explanation

Among the given options, aluminum (Al) has the highest melting point. This is because aluminum has stronger metallic bonds due to its higher electronegativity and smaller atomic radius compared to the other options. Stronger metallic bonds require more energy to overcome, resulting in a higher melting point.

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Which one is a metalloid?

Tin

Germanium

Sulphur

Carbon

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Explanation

(b) it shows intermediate properties between metals and non metals.

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Zn and Cd do not show variable valency like 'd' block elements due to :

Softness

Completed 'd' orbital

two electrons in outermost orbit

low m.p.

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Explanation

(b) It is a fact.

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In the long form of periodic table, the elements having lowest ionization potential are placed in:

I group

IV group

VII group

Zero group

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Explanation

(a) Ionization potential increases along period.

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Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?

3d³,4s²

3d⁵,4s¹

3d⁵,4s²

3d²,4s²

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Explanation

(c)

For transition metal elements a general rule is = The max number of oxidation states = no. unpaired d-orbital electrons + the 2s electrons.

In 3d⁵4s²configuration

Number of unpaired d-electrons = 5

Hence Maximum number of oxidation states = 5+2=7

Such as Mn⁺⁷

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The law of triads applicable to a group of:

Cl, Br, I

C, N, O

Na, K, Rb

H, O, N

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Explanation

(a) The average atomic mass of,

Br= $\frac{At . wt . of Cl + At . wt . of I}{2}$

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In the long form of periodic table all the non-metals are placed under:

s-block

p-block

f-block

d-block

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Explanation

s,d ,f block have metal only , where as p block has metal, nonmetal and metalloid .

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