Chemistry NEET Questions — Free MCQ Practice

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Chemistry MCQs for NEET — Practice Questions with Answers

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Z_eff of Na⁺ and Na⁰ are respectively :-

1.95 and 1.22

0.85 and 0.35

1 and 0.35

6.85 and 2.2

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Explanation

apply slatter rule

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Removal of 2^ndelectron is always :-

Endothermic

Endothermic for Mg, Be, N

Exothermic for Mg, Be, N and noble gases

Depends of electronic configuration

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Explanation

removal of electron from cation is always endo thermic

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Actinide contraction is mainly related to :-

Poor shielding by 5f subshell

Extra ordinary decrement in Z_eff

Both of the above

Strong shielding by 5f subshell

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Atomic radius of Be, O, C, N, B are respectively (in pm) :-

111, 66, 77, 74, 88

74, 84, 111, 77,66

111, 88, 77, 74, 66

111, 66, 88, 77,74

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Explanation

radius decreases from left to right in P.T

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First four IP values of an element are 19, 190, 230 and 260 eV/atom. Element belongs to:-

Amphoteric elements

Four electron donor group

s-block

All of the above

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Explanation

IE $\propto O . S$

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A large difference between fifth and sixth ionisation energies indicate the element having :-

15 proton in nucleus

13 proton in nucleus

11 proton in nucleus

Ionisation energy is NOT related to number of proton in nucleus

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Explanation

group 15, has I.E₆ >>>>I.E₅

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If atomic number of an element of He-family is Z then which of the following atomic number will highest IP?

Z - 2

Z - 1

Z + 1

Z + 2

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Explanation

n-1 = grp 17

n - 2 = grp 16

n + 1 = grp 1

n + 2 = grp 2

so grp 17 will have highest I.E

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The element having very high electron affinity but zero ionisation enthalpy is :-

He (due to inert gas configuration)

Be (due to full filled subshell)

H (due to presence of allotropes)

None of the above

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The pair of which addition of 2^nd electron in both the atoms are endothermic :-

N, Ne

Be, F

B, C

All of the above

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Explanation

Addition of 2nd electron is always endothermic.

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In which of the following options the order of arrangement does not agree with the variation of property indicated against it?

B < C < N < O (increasing first ionisation enthalpy)

I < Br < F < Cl (increasing electron gain enthalpy)

Li < Na < K < Rb (increasing metallic radius)

Al³⁺ < Mg²⁺ < Na⁺ <F^- (increasing ionic size)

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Explanation

(a)

For option (a)

First ionisation energy is the energy required to remove an electron from outermost shell.

Hence, correct order is B < C < O < N.

For option (b)

Electron gain enthalpy is the energy required to gain an electron in the outermost shell.

Hence, the correct order is I < Br < F < Cl.

For option (c)

As we move down the group in alkali metal, metallic radius increases Li < Na < K < Rb.

For option (d)

In case of isoelectronic species, as positive charge decreases or negative charge increases the ionic size of the species increases and vice-versa Al³⁺ < Mg²⁺ < Na⁺ <F^- .

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Frequently Asked Questions

Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.