Chemistry MCQs for NEET — Practice Questions with Answers

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IP1 and IP2 Mg are 178 and 348  Kcal mol-1 . The energy required for the reaction, 

                                       MgMg2+ + 2e- is :

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Explanation

(b)  Removal of two electrons (one by one ) from an atom requries energy = IP1 + IP2.

Which of the following characteristics regarding halogens is not correct?

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Explanation

(c) Electron affinity order for halogen is Cl>F>Br>I .

The process requiring the absorption of energy is :

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Explanation

(d) EA1 for elements is exothermic and EA2 is endothermic. Also EA2 for O>EA1 for O.

Which of the following orders is correct for the size?

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Explanation

(D) (1) Mg2+, Na+ and F- are isoelectronic and thus follows the order M12g2+<N11a+<F-9.

Al belongs to third period and has no charge so it is largest.

Na+=102 pm; Mg2+=72 pm; Al =143 pm, F-=133 pm.

 K+= has more number of shells than Mg2+ and Al3+ and Mg2+ are isoelectronic but Al3+ has higher nuclear charge so Al3+<Mg2+. Mg2+ and Li+ has diagonal relationship. But due to +2 charge in Mg2+, the Mg2+ is smaller than Li+. Hence Al3+ is the smallest one.

K+=1.38 A, Li2+=0.76 A, Mg2+=0.72 A and Al3+=0.535 A.

As the number of electrons are lost, the attraction between valence shell electrons and nucleus increases. As a consequence of this the electrons are pulled closer to the nucleus leading to the contraction in size of ions.

Across the period the nuclear charge increases and thus the size of atoms decreases.

Mg = 160 pm; Al = 143 pm; Si = 118; P = 110 pm.

The electron gain enthalpies of halogens in kJ mol-1 are as given below.

F =-332, Cl =-349, Br =-234, I =-295.

The least negative value for F as compared to that of Cl is due to:

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Explanation

(D) Due to small size of F atom, the electron-electron repulsions in compact 2-p sub shell are large and hence the incoming electron is not accepted with the same ease as is the case with Cl (less electron - electron repulsions)

Which of the following statements is not correct?

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Explanation

(A), (C) and (D) are correct statements 

(B) First decreases from B to Al and then increases marginally owing to discrepancies in atomic size of the element.

Which of the following orders is correct?

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Explanation

(D) (A) As electronegativity increases the non-metallic character increases as tendency to form anion increases.

(B) It is based on their SRP values. (Oxidising power may be cumulative effect of hydration energies, electronegativities, bond dissociation energies and electron gain enthalpies)

(C) C =-121; Si = -135; P =-60; N = +31 (all values are in KJ/mole). It depends on various factors like size of atom, nuclear charge, partially filled, half filled and completely filled electronic configurations.

If the same element is forming oxides in different oxidation states then :

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Explanation

(B) Oxidation state  electronegativity.

Electronegativity increases with increase in oxidation state; so the difference in electronegativity decreases (between element and oxygen) and acidic character increases.

Assertion : The 5th period of periodic table contains 18 elements and not 32.

Reason : n = 5, –1 = 0, 1, 2, 3. The order in which the energy of available orbits 4d, 5s and 5p increases is 5s < 4d < 5p and the total number of orbitals available are 9 and thus 18 electrons can be accommodated.

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Explanation

The order in which the energy of available orbitals `4d,5s` and 5p increases is `5s lt 4d lt 5p` and the total number of orbitals avaiable are 9 and thus 18 electrons can be accommodated

Assertion : :The 4f- and 5f- inner transition series of elements are placed separately at
the bottom of the periodic table.

Reason : (i) This prevents the undue expansion of the periodic table i.e., maintains its structure.
(ii) This preserve the principle of classification by keeping elements with similar properties in a single column.

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Explanation

(A)

4f and 5f - inner transition series of elements are placed separately at the bottom of the periodic table. It is because 

1) It prevents the undue expansion of the periodic table i.e. maintains it's structure.
2) This preserves the principle of classification by keeping elements with similar properties in a single column.
 

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