Chemistry MCQs for NEET — Practice Questions with Answers

Among the given options, the molecular species S32- (trisulfur dianion) is not linear. It has a bent or V-shaped molecular geometry due to the presence of two terminal sulfur atoms bonded to the central sulfur atom with a bond angle less than 180°.

(d) In $SiC{l}_4$ difference between electronegativity of Si (1.8) and chlorine (3.0) is higher than in other given compounds 

(a) 

     (a) $\underset{\mathrm{Paramagnetic}}{\underset{\mathrm{BO} = 1.5}{{\mathrm{C}}_2^{+}}}\stackrel{}{\to }\underset{\mathrm{Diamagnetic}}{\underset{\mathrm{BO} = 2}{{\mathrm{C}}_2}}$                                  (b) $\underset{\mathrm{Diamagnetic}}{\underset{\mathrm{BO} = 3}{{\mathrm{NO}}^{+}}}\underset{}{\to }\underset{\mathrm{Paramagnetic}}{\underset{\mathrm{BO} = 2.5}{\mathrm{NO}}}$

      (c) $\underset{\mathrm{Paramagnetic}}{\underset{\mathrm{BO} = 2}{{\mathrm{O}}_2}}\stackrel{}{\to }\underset{\mathrm{Paramagnetic}}{\underset{\mathrm{BO} = 2.5}{{\mathrm{O}}^{+}}}$                                (d) $\underset{\mathrm{Diamagnetic}}{\underset{\mathrm{BO} = 3}{{\mathrm{N}}_2}}\underset{}{\to }\underset{\mathrm{Paramagnetic}}{\underset{\mathrm{BO} = 2.5}{{\mathrm{N}}_2^{+}}}$

(c) More effective axial and sideways overlapping between atomic orbitals of carbon and those of oxygen atom is higher due to smaller size of oxygen atom. oxygen is more electronegative than oxygen atom, due to these factor CO has highest bond energy .

(a)  According to coulsion model, H.O.M.O. (Highest Occupied Molecular Orbital) of CO molecular 

       is non-bonding M.O. with slight antibonding character.

The incorrect match is trigonal bipyramidal electron geometry leading to a triangular planar molecular shape. Trigonal bipyramidal electron geometry should result in a molecular shape that is either trigonal bipyramidal or seesaw-shaped, but not triangular planar.

(c) $\sigma ‐$bonding molecular orbital is gerade due to having center of symmetry.