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Chemistry NEET Questions — Free MCQ Practice

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Give the correct order of initials T and F for following statements. use T if statement is true and F if it is false :

(a) The order of repulsion betweeen different pair of electrons is $l_{p} - l_{p} > l_{p} - b_{p} > b_{p} - b_{p}$

(b) In general , as the number of lone pair of electrons on central atom increases, value of bond angle from normal bond angle also increases

(c) The number of lone pair on O in $H_{2} O$ is 2 while on N in $N H_{3}$ is 1

(d) The structure of xeon fluorides and xenon oxyfluorides could not be explained on the basis of VSEPR

A.

TTTF

B.

TFTF

C.

TFTT

D.

TFFF

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Explanation

(b) (ii) (F) In general as the number of lone pair electrons on central atom increases , value of bond angle from normal bond angle decreases due to $l_{p} - l_{p} > l_{p} - b_{p}$

(iv) (F) Structures of xeon fluorides and xeon oxyfluride are explained on the basis VSEPR theory.

In SO $B r_{2,}$ S-O bond has maximum bond length in comparison to S-O bond lengths in $S O F_{2}$ and $S O C l_{2},$ because in $S O B r_{2}$ , S-O bond has been formed by hybrid orbital containing less s- character .

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Which species is planar?

A.

$C {O_{3}}^{2 -}$

B.

$S {O_{3}}^{2 -}$

C.

$C l {O_{3}}^{-}$

D.

$B {F_{4}}^{-}$

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Incorrect statement is:

A.

$A l F_{3} > M g O > M g F_{2}$ : Lattice energy

B.

$L i > N a > A l > M g$ : Electon affinity

C.

$S F_{6} > P F_{5} > S i F_{4}$ : Lewis acidic character

D.

$S I C I_{4} > S i B r_{4} > S i l_{4}$ : Decreasing ionic character

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Explanation

(c) Correct order of lewis acidic character: $P F_{5} > S i F_{4} > S F_{6}$ Although, S has vaccant 3d-orbitals but it cannot accept co-ordinate bond from Lewis base due to steric crowding factor as S-atom is already bonded to six F-atoms.

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What is the geometry of the $I B {r_{2}}^{-}$ ion ?

A.

Linear

B.

Bent shape with bond angle of about $90 °$

C.

Bent shape with bond angle of about $109 °$

D.

Bent shape with bond angle of about $120 °$

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What is the shape of the $C l F_{3}$ molecule?

A.

Trigonal planar

B.

Trigonal pyramid

C.

T-shaped

D.

Tetrahedral

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Which of the following species/molecules does not have same number of bond pairs and lone pairs?

A.

$O C N^{-}$

B.

$H_{2} O$

C.

$C_{2} H_{2} C l_{2}$

D.

$O_{3}$

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$O_{2} F_{2}$ is an unstable yellow orange solid and $H_{2} O_{2}$ is a colourless liquid both have O $—$ O bond and

O $—$ O bond length in $H_{2} O_{2}$ and $O_{2} F_{2}$ respectively is:

A.

1.22 A, 1.48

B.

1.48 A, 1.22A

C.

1.22 A, 1.22A

D.

1.48 A, 1.48A

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The bond length of the S $—$ O bond in maximum in which of the following compounds?

A.

$S O C I_{2}$

B.

$S O B r_{2}$

C.

$S O F_{2}$

D.

All have the same length

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solubillity of alkali metal fluorides increases down the group select correct explanation for given statement :

A.

Hydration energy increase and lattice energy decrease down the group

B.

both energy decrease down the group but decrease in hyderation energy is rapid

C.

both energy decrease down the group but decrease in lattice energy is rapid

D.

both energy decrease down the group but increase in hyderation energy is rapid

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Explanation

(c) Althogh both hyderation and lattice energies of alkali metal flourides decrease down the group and hyderation energy dominate ove lattice energy, therefore, solubility increase down the group.

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In which of the following compounds B $—$ F bond length is shortest ?

A.

$B {F_{4}}^{-}$

B.

$B F_{3} \leftarrow N H_{3}$

C.

$B F_{3}$

D.

$B F_{3} \leftarrow N {(C H_{3})}_{3}$

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Explanation

(c) Only in $B F_{3}$ p $π$ -p $π$ back bonding is possible due to which B $—$ F bond length is shortest. In order compounds, p-orbital at boron is not possible.

Water molecules are hexagonally closed packed in ice with the help of H-bonds, hence due to existance of voids/interstitial spaces it has cage like structure with less density than water.

Chemistry MCQs for NEET — Practice Questions with Answers

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