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Chemistry MCQs for NEET — Practice Questions with Answers

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If ${CdI}_{2}$ is pink in colour, the ${CdCl}_{2}$ will be '.............' coloured.

yellow

red

blue

cannot be predicted

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Explanation

(d) In ${CDI}_{2}$ , Pink colour is due to polarization of $I^{-} by {Cd}^{2 +}$ has pseudo noble gas configuration. In ${CdCI}_{2}$ , extent of polarization of ${Cl}^{-} by {Cd}^{2 +}$ is relatively less, hence specific colour cannot be predicted.

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Which are true statements among the following?

$P H_{5}$ and $B i C l_{5}$ does not exist

$p π$ - $d π$ bonds are present in $S O_{2}$

Electrons travel with speed of light

$S e F_{4}$ and $C H_{4}$ has same changes

(5) ${I_{3}}^{+}$ has bent geometry

(a) 1,3

(b) 1,2,5

(d) 1,2,4

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Explanation

(b)I3 + has a bent shape which is sp3 hybridized. The central atom iodine atom has 6 electrons because of one positive charge, it will make single bonds with 2 I atoms to complete their and it`s own octet, keeping the loan pair upside we get a bent shape.

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In which molecule all atoms are coplanar?

$C H_{4}$

$B F_{3}$

$P F_{3}$

$N H_{3}$

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Explanation

(b) Due to $s p^{2}$ - hybridization.

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Which species does not exist?

${(S n C l_{6})}^{2 -}$

${(G e C l_{6})}^{2 -}$

${(C C l_{6})}^{2 -}$

${(S i C l_{6})}^{2 -}$

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Explanation

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Which is paramagentic?

$C l_{2} O_{6}$

$C l_{2} O_{7}$

$C l_{2} O$

$C l O_{2}$

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Explanation

(d) $C l O_{2}$ has 33 electrons ; one will be unpaired

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Greater the dipole moment:

greater is the ionic nature

lesser the polarity

smaller is the ionic nature

none of these

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Explanation

(a) more is the dipole moment more is ionic nature. $μ = δ \times d;$ higher is $μ$ , more will be $δ$ on that atom.

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$N F_{3}$ is:

non-polar compound

electrovalent compound

having low value of dipole moment than $N H_{3}$

having more dipole moment than $N H_{3}$

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Explanation

(c) Inspite of three polar bond,the lone pair of electrons on N atom decreases the dipole moment of $N F_{3}$ than $N H_{3}$ because in NH3 , dipole moment is getting added ,where as in NF3, dipole moment is being substracted.

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Polarization of electrons in acrolein may be written as:

$\overset{δ^{-}}{C} H_{2} = C H - \overset{δ^{+}}{C} H = O$

$\overset{δ^{-}}{C} H_{2} = C H - C H = \overset{δ^{+}}{O}$

$\overset{δ^{-}}{C} H_{2} = \overset{δ^{+}}{C} H - C H = O$

$\overset{δ^{+}}{C} H_{2} = C H - C H = \overset{δ^{-}}{O}$

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Explanation

(d) O is more electronegative than C.

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$P C l_{5}$ exists but $N C l_{5}$ does not because:

nitrogen has no vacant 2d-orbitals

$N C l_{5}$ is unstable

nitrogen atom is much smaller than p

nitrogen is highly inert

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Explanation

(a) Thus, excitation of 2s-electron in N is not possible.and N doesnot have vacent d sub shell.

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Bond angle between two hybrid orbitals is $105^{°}$ .% S character orbital is:

between 30-31%

between 19-20%

between 25 -26%

between 22-23%

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Explanation

(d) Nearer to 25%, the angle is $109^{°}$ 28' for $s p^{3}$ -hybridization.

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