Chemistry MCQs for NEET — Practice Questions with Answers

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A diatomic molecule has a dipole moment of 1.2 D. If its bond length is equal to 10 -10 m then the fraction of an electronic charge on each atom will be:

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Explanation

(D) μ=q×d

1.2×10-18=q×10-8cm

q=1.2×10-1810-8=1.2×10-10%charge =qe×=1.2×10-104.8×10-10×100=25%

Which of the following statements is correct?

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Explanation

All the given statements are correct. (CH3)3COH is less acidic than (CH3)3SiOH due to the poorer ability of silicon to stabilize the negative charge on the conjugate base. CO is a stable molecule, but its silicon analogue is not stable. In phosgene (COCl2), the C-O bond length is longer than expected due to the presence of resonance, while the C-Cl bond length is shorter.

The increasing order of the strength of hydrogen bond in the following mentioned linkages
is

(i) O — H — S     (ii) O — H  — O    (iii) F – H – F   (iv) F – H – O

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Explanation

(A) Strength of H-bonds on following factors.
      (i) Electronegativity of element covalently bonded to hydrogen atom.
      (ii) Size of electronegative element.
      (iii) Ease of donation of lone pair of electrons by electronegative element.

The boiling pot of CCl4 is higher than that of CHCl3 because :

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Explanation

(C)  Number of polarisable electrons  strength of vander waal’s force  boiling point.
       boiling point CHCl3=61°C and CCl4=73°C.

Assertion : In tetrahedral hybridisation i.e., in sp3 hybridisation all p-orbitals are involved and no

                   p-orbital is left for coming with π-bonds.

Reason : Central atom can not form double bonds in the molecules or species having sp3hybridisation.

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Explanation

The assertion is true because in sp3 hybridization, all four orbitals are involved in sigma (σ) bonding, and no p-orbital is left for pi (π) bond formation. However, the reason is false because the central atom can form double bonds in molecules or species with sp2 hybridization, where one p-orbital is available for π-bond formation.

Assertion : N2F3+ is planar at each nitrogen atom.

Reason : N3H, the bond angle HNN is 120° and both the NH bond lengths are not equal.

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Assertion : Carbon has unique ability to form - multiple bonds with itself and with other

                  atoms of small size and high electronegativity.

Reason : Heavier elements of group 14th do not form - multiple bonds with itself because

               their atomic orbitals are too large and diffuse to have effective overlapping.

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Explanation

(B) Both Assertion and Reason are true statements but are different and reason is

      not true explanation of assertion. High electronegativity of atoms attached to carbon atom

      indirectly results into the contraction of the size of p-orbitals. As carbon atomic size is smaller

      and thus it has effective overlapping.

Assertion : NO+ and CN- both have same bond order and magnetism

Reason : NO+ and CN- are isoelectornic species.

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Explanation

(A) Number of electrons NO+ = 7+8-1 = 14

      Number of electrons CN- = 6+7+1 = 14

      Bond order = 10-42=3

      Both are diamagnetic.

Assertion : Crystals of hydrated calcium sulphate gypsum : CaSO4, 2H2O are soft and easily cleaved.

Reason : Crystals of anhydrous calcium sulphate anhydrite : CaSO4 are very hard and very difficult

               to cleave.

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Explanation

(B) Within the Ca2+/SO42- layers the ions are held together by strong electrovalent bonds. But

      these separated Ca2+/SO42- layers linked by relative weak H-bond. The weaker H-bonds and

      stretched along the layer of water molecules.

      Anhydride has a completely ionic structure involving only Ca2+ and SO42- ions.

When two atoms combine to form a molecule

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Explanation

To attain stability energy is released.

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