Chemistry MCQs for NEET — Practice Questions with Answers

Practice free Chemistry NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Register free to filter questions

It is found that v forms a double salt isomorphous with Mohr's salt. The oxidation number of V in this compound is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) VSO4 is isomorphous to,FeSO4.(NH4)2SO4.6H2O.

The correct order of reducing power of halide ions is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) Due to higher EOP° order. 

When H2SO3 is converted into H2SO4 the change in the oxidation state of sulphur is from:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) S4+ S6+ + 2e

In which of the following processes nitrogen is oxidised?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) 2N3- N2O + 6e

In which reaction is hydrogen acting as an oxidising agent?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) 2e + H202H1-

Li Li1+ + e

H2 is reduced and thus, oxidant.

Fluorine is a strong oxidising agent because:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) Due to smallest halogen, it possesses maximum tendency for accepting electron in aqueous medium.

(1/2) F2+e+aq F-H=-ve(max.for F2)

The oxidation state of Ni in Ni(CO)4 is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Ox. no. of Ni is equal to zero.

Milliequivalents of a solute in a solution can be given by:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) These are formulae of Meq.

HBr and HI reduce H2SO4, HCl can reduce KMnO4 and HF can reduce:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) F- can be oxidised to F2 only by electroysis.

Sulphurous acid can be used as:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(d) S in H2SO3 is in +4 oxidation state. It lies in between its maximum and minimum oxidation state, i.e., +6 and -2 and thus, S can increase or decrease its ox. no. as the case may be.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.